Using a dictionary to select function to execute

2019-01-08 11:08发布

I am trying to use functional programming to create a dictionary containing a key and a function to execute:

myDict={}
myItems=("P1","P2","P3",...."Pn")
def myMain(key):
    def ExecP1():
        pass
    def ExecP2():
        pass
    def ExecP3():
        pass
        ...
    def ExecPn():
        pass  

Now, I have seen a code used to find the defined functions in a module, and I need to do something like this:

    for myitem in myItems:
        myDict[myitem] = ??? #to dynamically find the corresponding function

So my question is, How do I make a list of all the Exec functions and then assign them to the desired item using the a dictionary? so at the end I will have myDict["P1"]() #this will call ExecP1()

My real problem is that I have tons of those items and I making a library that will handle them so the final user only needs to call myMain("P1")

I think using the inspect module, but I am not so sure how to do it.

My reason to avoid:

def ExecPn():
    pass
myDict["Pn"]=ExecPn

is that I have to protect code as I am using it to provide a scripting feature within my application.

9条回答
倾城 Initia
2楼-- · 2019-01-08 11:19

Simplify, simplify, simplify + DRY:

tasks = {}
task = lambda f: tasks.setdefault(f.__name__, f)

@task
def p1():
    whatever

@task
def p2():
    whatever

def my_main(key):
    tasks[key]()
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别忘想泡老子
3楼-- · 2019-01-08 11:20

This will call methods from dictionary

This is python switch statement with function calling

Create few modules as per the your requirement. If want to pass arguments then pass.

Create a dictionary, which will call these modules as per requirement.

    def function_1(arg):
        print("In function_1")

    def function_2(arg):
        print("In function_2")

    def function_3(fileName):
        print("In function_3")
        f_title,f_course1,f_course2 = fileName.split('_')
        return(f_title,f_course1,f_course2)


    def createDictionary():

        dict = {

            1 : function_1,
            2 : function_2,
            3 : function_3,

        }    
        return dict

    dictionary = createDictionary()
    dictionary[3](Argument)#pass any key value to call the method
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小情绪 Triste *
4楼-- · 2019-01-08 11:24
#!/usr/bin/python

def thing_a(arg=None):
    print 'thing_a', arg

def thing_b(arg=None):
    print 'thing_b', arg

ghetto_switch_statement = {
    'do_thing_a': thing_a,
    'do_thing_b': thing_b
}

ghetto_switch_statement['do_thing_a']("It's lovely being an A")
ghetto_switch_statement['do_thing_b']("Being a B isn't too shabby either")

print "Available methods are: ", ghetto_switch_statement.keys()
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祖国的老花朵
5楼-- · 2019-01-08 11:25

You are wasting your time:

  1. You are about to write a lot of useless code and introduce new bugs.
  2. To execute the function, your user will need to know the P1 name anyway.
  3. Etc., etc., etc.

Just put all your functions in the .py file:

# my_module.py

def f1():
    pass

def f2():
    pass

def f3():
    pass

And use them like this:

import my_module

my_module.f1()
my_module.f2()
my_module.f3()

or:

from my_module import f1
from my_module import f2
from my_module import f3

f1()
f2()
f3()

This should be enough for starters.

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成全新的幸福
6楼-- · 2019-01-08 11:25

You can just use

myDict = {
    "P1": (lambda x: function1()),
    "P2": (lambda x: function2()),
    ...,
    "Pn": (lambda x: functionn())}
myItems = ["P1", "P2", ..., "Pn"]

for item in myItems:
    myDict[item]()
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闹够了就滚
7楼-- · 2019-01-08 11:33
# index dictionary by list of key names

def fn1():
    print "One"

def fn2():
    print "Two"

def fn3():
    print "Three"

fndict = {"A": fn1, "B": fn2, "C": fn3}

keynames = ["A", "B", "C"]

fndict[keynames[1]]()

# keynames[1] = "B", so output of this code is

# Two
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