Zend Framework URL - How to pass a query string?

2019-06-06 00:21发布

I have this link:

<a href="<?php echo $this->url(array('controller'=>'index','action'=>'form'),NULL,TRUE);?>">
                                    Form
</a>

With this I get something like:

http://foo.com/form

I need to pass a param to the URL with this link. So that I can have something like this instead:

http://foo.com/form?bar=1231

How can we accomplish this ?

Thanks in advance.

2条回答
beautiful°
2楼-- · 2019-06-06 00:32

In ZF, URL parameters are passed as /param-name/param-value. So if http://foo.com/form/bar/1231 would satisfy you, you could do like this:

<?php echo $this->url(array('controller'=>'index','action'=>'form', 'bar'=>'1231'),NULL,TRUE);?>
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▲ chillily
3楼-- · 2019-06-06 00:35

The URL view helper is used to create links using the Routes setup with your application. If you aren't following the routes setup, then there isn't much point in using the view helper, and instead you could just append the created url you got from the view helper with the ?bar=1231.

<a href="<?php echo $this->url(array('controller'=>'index','action'=>'form'),NULL,TRUE)."?bar=1231";?>">
                                    Form
</a>
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