Dynamically serving django docker containers

2019-06-04 04:12发布

I'm creating a service in which django containers are spawned on demand for users to test backend-functionality online.

I would like to make the spawned instances available to users on main domain:

Example: User spawns container userapp which exposes port 8000, it should be accessible on my domain as mydomain.net/userapp/

I do not know the amount of instances running, or their names in advance.

I found a nginx-proxy container here which dynamically creates configs for nginx to serve containers to subdomains:

$ docker run -e VIRTUAL_HOST=userapp.mydomain.com ...

I would like to have it accessible on the path. How can I create dynamic proxy paths with nginx or django?

1条回答
Fickle 薄情
2楼-- · 2019-06-04 05:16

I figured this out with django-http-proxy.

I can inherit from HttpProxy and create a DynProxyView:

views.py

from httpproxy.views import HttpProxy

class DynProxyView(HttpProxy):
    def get_object(self):
        return Fiddle.objects.get(pk=self.kwargs['pk'])
    rewrite = True
    @property
    def base_url(self):
        url= self.request.scheme+"://localhost:" + str(self.get_object().port)
        print url
        return url
    def get_full_url(self, url):
        result = super(DynProxyView, self).get_full_url(url)
        return result[:-1] # To get rid of a pesky redundant slash

urls.py

...
url(r'^(?P<pk>[-\w]+)/result/(?P<url>.*)$', DynProxyView.as_view(),name='result'),
...

models.py

class Fiddle(models.Model):
    name = models.CharField(max_length=20, unique=True)
    hash = models.CharField(max_length=32, null=True, blank=True)
    port = models.IntegerField(null=True, blank=True)

This way I can get the desired effect.

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