How to disable TouchUpInside Action outside the bo

2019-06-01 01:18发布

This is my Xib. I just dragged a UIButton and changed its background color.

enter image description here

I created a semi circle layer using this code

    let circlePath = UIBezierPath.init(arcCenter: CGPointMake(mybutton.bounds.size.width / 4, 0), radius: mybutton.bounds.size.height, startAngle: 0.0, endAngle: CGFloat(M_PI), clockwise: true)
    let circleShape = CAShapeLayer()
    circleShape.path = circlePath.CGPath
    mybutton.layer.mask = circleShape

and this is my output.

enter image description here

Its perfect as I want it. But the problem is that this button is clickable outside its rounded area(as per actuall shape of button). I want it to be clickable only as rounded shape.

How can I achieve this ? Thanks.

1条回答
虎瘦雄心在
2楼-- · 2019-06-01 01:26

Create action of signature

- (IBAction)buttonPressed:(id)sender forEvent:(UIEvent*)event{
//your code
} 

for your button

Find out touch location using this answer UIButton TouchUpInside Touch Location

Check if that location is contained in your CGPath using

- (IBAction)buttonPressed:(id)sender forEvent:(UIEvent*)event{
  //find location point using above answer link
  if([button.layer.mask containsPoint: location])
  {
   //proceed with the code
  }
} 

it returns a bool if it contains point.

i.e if it contains point you can proceed otherwise you can return.

Hope it helps :)

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