How to read if a checkbox is checked in PHP?

Question

How to read if a checkbox is checked in PHP?

Answer 1

If your HTML page looks like this:

<input type="checkbox" name="test" value="value1">

After submitting the form you can check it with:

isset($_POST['test'])

or

if ($_POST['test'] == 'value1') ...

Answer 2

When using checkboxes as an array:

<input type="checkbox" name="food[]" value="Orange">
<input type="checkbox" name="food[]" value="Apple">

You should use in_array():

if(in_array('Orange', $_POST['food'])){
  echo 'Orange was checked!';
}

Remember to check the array is set first, such as:

if(isset($_POST['food']) && in_array(...

Answer 3

$is_checked = isset($_POST['your_checkbox_name']) &&
              $_POST['your_checkbox_name'] == 'on';

Short circuit evaluation will take care so that you don't access your_checkbox_name when it was not submitted.

Answer 4

in BS3 you can put

  <?php
                  $checked="hola";
                  $exenta = $datosOrdenCompra[0]['exenta'];
                  var_dump($datosOrdenCompra[0]['exenta']);
                  if(isset($datosOrdenCompra[0]['exenta']) and $datosOrdenCompra[0]['exenta'] == 1){

                      $checked="on";

                  }else{
                    $checked="off";
                  }

              ?>
              <input type="checkbox" id="exenta" name="exenta" <?php echo $checked;?> > <span class="label-text"> Exenta</span>

Please Note the usage of isset($datosOrdenCompra[0]['exenta'])

Answer 5

You can check the corresponding value as being set and non-empty in either the $_POST or $_GET array depending on your form's action.

i.e.: With a POST form using a name of "test" (i.e.: <input type="checkbox" name="test"> , you'd use:

if(isset($_POST['test']) {
   // The checkbox was enabled...

}

Answer 6

You can do it with the short if:

$check_value = isset($_POST['my_checkbox_name']) ? 1 : 0;

or with the new PHP7 Null coalescing operator

$check_value = $_POST['my_checkbox_name'] ?? 0;