Let's say I have an arbitrary string that's ~1000 bytes long. (I'm studying crypto.) How can I unpack that into a BigNum? I understand how to pack it into 8-bit numbers, say, or 32-bit numbers.
s='I am a grumpy potato'
s.unpack('C*')
[73, 32, 97, 109, 32, 97, 32, 103, 114, 117, 109, 112, 121, 32, 112, 111, 116, 97, 116, 111]
s.upack('L*')
=> [1835081801, 1730175264, 1886221682, 1869619321, 1869898100]
Or, is there a straightforward way to combine, say, the 8-bit numbers into a BigNum? I could probably unpack into an array of 8-bit numbers and multiply each element of the array by subsequent powers of 8. But that seems too complicated to be the right way.
EDIT: What's the preferred way to turn the BigNum back into a string? I don't mean to_s, I mean taking the same pattern of bytes and interpreting it as a string?
Thanks a lot for https://stackoverflow.com/a/17014450/204070. Works wonderful for me. The answer could be simplified to:
I think your hunch about how to handle it is right. Unpack doesn't handle Bignums; they're classically fairly tricky specifically because they don't fit in a standard 64-bit int.
You could manually "unpack" it, via something like:
That is, reverse the list of bytes (if on a big endian system), iterate each byte, and multiply its value by
256^position
. Ruby's BigNum kicks in once the value gets big enough, and you're able to convert byte strings into very large numbers without a hitch.You can do the same in chunks of 32-bit (or 64-bit, if the platform supports it) ints, as well: