MySQL Workbench - Forward Engineering - Error 1005

2019-05-24 21:25发布

I am on MacOSX using MySQL Workbench 5.2.45 I have designed a database using the EER Diagram functionality and then tried the forward engineering to generate my database to put on my local server. I get the error code: Error 1005: Can't create table (errno: 150)

SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;
SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL,ALLOW_INVALID_DATES';

CREATE SCHEMA IF NOT EXISTS `Finance` DEFAULT CHARACTER SET utf8 COLLATE utf8_general_ci ;
USE `Finance` ;

-- -----------------------------------------------------
-- Table `Finance`.`DatabaseUser`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `Finance`.`DatabaseUser` (
  `ID` INT(11) NOT NULL AUTO_INCREMENT ,
  `FirstName` VARCHAR(255) NOT NULL ,
  `LastName` VARCHAR(255) NOT NULL ,
  `Tel` VARCHAR(255) NULL ,
  `Email` VARCHAR(255) NOT NULL,
  `Password` VARCHAR(255) NOT NULL ,
  `Admin` CHAR(1) NOT NULL DEFAULT 'N' ,
  `Project1` CHAR(1) NOT NULL DEFAULT 'N' ,
  `Project2` CHAR(1) NOT NULL DEFAULT 'N' ,
  `Project3` CHAR(1) NOT NULL DEFAULT 'N' ,
  PRIMARY KEY (`ID`) )
ENGINE = InnoDB;


-- -----------------------------------------------------
-- Table `Finance`.`Entities`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `Finance`.`Entities` (
  `ID` INT(11) NOT NULL AUTO_INCREMENT ,
  `CreatorID` INT(11) NOT NULL ,
  `FullName` VARCHAR(255) NOT NULL ,
  `ShortName` VARCHAR(255) NULL ,
  PRIMARY KEY (`ID`) ,
  INDEX `Creator_idx` (`CreatorID` ASC) ,
  CONSTRAINT `CreatorEntities`
    FOREIGN KEY (`CreatorID` )
    REFERENCES `Finance`.`DatabaseUser` (`ID` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

-- -----------------------------------------------------
-- Table `Finance`.`Grant`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `Finance`.`Grant` (
  `ID` INT(11) NOT NULL AUTO_INCREMENT ,
  `CreatorID` INT(11) NOT NULL ,
  `DonorID` INT(11) NOT NULL ,
  `RecipientID` INT(11) NOT NULL ,
  `Name` VARCHAR(255) NOT NULL ,
  `Year` YEAR NOT NULL ,
  PRIMARY KEY (`ID`) ,
  INDEX `Creator_idx` (`CreatorID` ASC) ,
  INDEX `index3` (`DonorID` ASC, `RecipientID` ASC) ,
  CONSTRAINT `CreatorGrant`
    FOREIGN KEY (`CreatorID` )
    REFERENCES `Finance`.`DatabaseUser` (`ID` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `InstrumentGrant`
    FOREIGN KEY (`DonorID` , `RecipientID` )
    REFERENCES `Finance`.`Entities` (`ID` , `ID` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

USE `Finance` ;


SET SQL_MODE=@OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS;

I have been trying the solutions suggested in the post (Error Code: 1005. Can't create table '...' (errno: 150)) but this doesn't seem to be the problem. 1. The datatypes are the same 2. I'm referencing primary keys 3. Foreign key names are unique 4. Tables are all InnoDB 5. No SET NULL involved etc.

Can you please help?

2条回答
我想做一个坏孩纸
2楼-- · 2019-05-24 21:36

Resolved:

In export menu, select "Generate Separate CREATE INDEX Statements" option in order to avoid this error.

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Explosion°爆炸
3楼-- · 2019-05-24 21:59

Change the foreign key constraint in Grant table.

Refer http://www.sqlfiddle.com/#!2/04945

  CONSTRAINT `InstrumentGrant`
    FOREIGN KEY (`RecipientID`)
    REFERENCES `Entities` (`ID`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `InstrumentGrant_2`
    FOREIGN KEY (`DonorID`)
    REFERENCES `Entities` (`ID`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION

Name the constraint as you want.

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