rand() generating the same number – even with sran

2019-01-08 00:37发布

So, I'm trying to create a random vector (think geometry, not an expandable array), and every time I call my random vector function I get the same x value, though y and z are different.

int main () {
    srand ( (unsigned)time(NULL));
    Vector<double> a;
    a.randvec();
    cout << a << endl;
    return 0;
}

using the function

//random Vector
template <class T>
void Vector<T>::randvec()
{
    const int min=-10, max=10;
    int randx, randy, randz;

    const int bucket_size = RAND_MAX/(max-min);

    do randx = (rand()/bucket_size)+min;
    while (randx <= min && randx >= max);
    x = randx;

    do randy = (rand()/bucket_size)+min;
    while (randy <= min && randy >= max);
    y = randy;

    do randz = (rand()/bucket_size)+min;
    while (randz <= min && randz >= max);
    z = randz;
}

For some reason, randx will consistently return 8, whereas the other numbers seem to be following the (pseudo) randomness perfectly. However, if I put the call to define, say, randy before randx, randy will always return 8.

Why is my first random number always 8? Am I seeding incorrectly?

标签: c++ random srand
7条回答
你好瞎i
2楼-- · 2019-01-08 01:24

Not directly related to the code in this question, but I had same issue with using srand ((unsigned)time(NULL)) and still having same sequence of values being returned from following calls to rand().

It turned out that srand needs to called on each thread you are using it on separately. I had a loading thread that was generating random content (that wasn't random cuz of the seed issue). I had just using srand in the main thread and not the loading thread. So added another srand ((unsigned)time(NULL)) to start of loading thread fixed this issue.

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