Write each row of a spark dataframe as a separate

2019-05-21 07:35发布

I have Spark Dataframe with a single column, where each row is a long string (actually an xml file). I want to go through the DataFrame and save a string from each row as a text file, they can be called simply 1.xml, 2.xml, and so on.

I cannot seem to find any information or examples on how to do this. And I am just starting to work with Spark and PySpark. Maybe map a function on the DataFrame, but the function will have to write string to text file, I can't find how to do this.

2条回答
爷的心禁止访问
2楼-- · 2019-05-21 08:20

I would do it this way in Java and Hadoop FileSystem API. You can write similar code using Python.

List<String> strings = Arrays.asList("file1", "file2", "file3");
JavaRDD<String> stringrdd = new JavaSparkContext().parallelize(strings);
stringrdd.collect().foreach(x -> {
    Path outputPath = new Path(x);
    Configuration conf = getConf();
    FileSystem fs = FileSystem.get(conf);
    OutputStream os = fs.create(outputPath);
});
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贪生不怕死
3楼-- · 2019-05-21 08:24

When saving a dataframe with Spark, one file will be created for each partition. Hence, one way to get a single row per file would be to first repartition the data to as many partitions as you have rows.

There is a library on github for reading and writing XML files with Spark. However, the dataframe needs to have a special format to produce correct XML. In this case, since you have everything as a string in a single column, the easiest way to save would probably be as csv.

The repartition and saving can be done as follows:

rows = df.count()
df.repartition(rows).write.csv('save-dir')
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