'this' keyword, not clear

2019-01-07 21:42发布

I get confused about 'this' keyword in the following codes, there are two 'this':

var Foo = function(string){
  this.name=string // 1st-this
}

Foo.prototype.get_name = function(){
  return this.name // 2nd-this
}

var myFoo = new Foo('John')

the_name=myFoo.get_name()

'the_name' is equal to 'John', the prototype method get the name by return this.name. But can anyone explain to me the 1st-this and 2nd-this, what do they stand for?

8条回答
Summer. ? 凉城
2楼-- · 2019-01-07 22:17

this refers to the object invoking the function, which in this case is myFoo. When you construct myFoo as a new Foo('John') the this keyword enables you to set myFoo.name = 'John', so when you call myFoo.get_name() it will also let you return myFoo.name which equals John.

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乱世女痞
3楼-- · 2019-01-07 22:20

In your example they are the same, when you call this from a method you override in the prototype chain you are referring to the same thing as when calling this from within the constructor function.

It gets trickier when working with callbacks or when defining member variables in prototype methods.

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何必那么认真
4楼-- · 2019-01-07 22:26

wow all of these different answers, and only one of them even used the word "context"! Here is the straightforward answer to your question:

the this keyword is an object reference that points to the context object.

In your example, this refers to an instance of the Foo object.

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Root(大扎)
5楼-- · 2019-01-07 22:33

In Javascript, the value of this is dependent on the way you call the function.

There are 5 ways to call a function in JS, and they all have effect on this:

  1. new Foo(); <= here, you’re creating a new object, and this will reflect that new object
  2. Foo(); <= here, you're calling the function as-is, and this will be the global object(!)
  3. var obj = { foo: Foo };
    obj.foo();
    <= here, you're calling the function as a method of obj; this will be obj
  4. Foo.call(thisObject, arg1, arg2); <= here, you can specify the value of this in the first argument
  5. Foo.apply(thisObject, [args]); <= here, you can specify the value of this in the first argument

In 4 and 5, the difference between call and apply is that with call, you need to pass all the arguments separately, whereas with apply, you can pass an array containing all the arguments.

Note that in my example 2 above, the function should have been called foo instead of Foo. Since it’s impossible to know off-hand whether a function is supposed to be called with new or not, the consensus is to start the function name with a capital letter if it’s a constructor (and should be used with new); otherwise, it should start with lowercase.

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我欲成王,谁敢阻挡
6楼-- · 2019-01-07 22:34

When you use the new keyword this is the instance object that you are creating.

var foo = new Bar();

i.e. the instance of Bar being assigned to foo


When you don't, this is the object on which the method you are calling lives.

var baz = foo.thing();
var boz = thing();

i.e. foo in the first example and window in the second (window is the default object).


You can also fritz with it using apply

var baz = foo.thing.apply(bar);

Here this (still inside the thing method) is bar)

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Rolldiameter
7楼-- · 2019-01-07 22:34

The "this" keyword always refers to the owner of the function. So for instance if you click on a button that accesses that function, this refers to that button. So if you have button A that has an onclick that calls that function then this is A.

In this case this would be John since in both cases they reference myFoo which is John since Myfoo is used in calling them

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