IllegalStateException: Can not perform this action

Question

I'm getting user reports from my app in the market, delivering the following exception:

java.lang.IllegalStateException: Can not perform this action after onSaveInstanceState
at android.app.FragmentManagerImpl.checkStateLoss(FragmentManager.java:1109)
at android.app.FragmentManagerImpl.popBackStackImmediate(FragmentManager.java:399)
at android.app.Activity.onBackPressed(Activity.java:2066)
at android.app.Activity.onKeyUp(Activity.java:2044)
at android.view.KeyEvent.dispatch(KeyEvent.java:2529)
at android.app.Activity.dispatchKeyEvent(Activity.java:2274)
at com.android.internal.policy.impl.PhoneWindow$DecorView.dispatchKeyEvent(PhoneWindow.java:1803)
at android.view.ViewGroup.dispatchKeyEvent(ViewGroup.java:1112)
at android.view.ViewGroup.dispatchKeyEvent(ViewGroup.java:1112)
at android.view.ViewGroup.dispatchKeyEvent(ViewGroup.java:1112)
at com.android.internal.policy.impl.PhoneWindow$DecorView.superDispatchKeyEvent(PhoneWindow.java:1855)
at com.android.internal.policy.impl.PhoneWindow.superDispatchKeyEvent(PhoneWindow.java:1277)
at android.app.Activity.dispatchKeyEvent(Activity.java:2269)
at com.android.internal.policy.impl.PhoneWindow$DecorView.dispatchKeyEvent(PhoneWindow.java:1803)
at android.view.ViewGroup.dispatchKeyEvent(ViewGroup.java:1112)
at android.view.ViewGroup.dispatchKeyEvent(ViewGroup.java:1112)
at android.view.ViewGroup.dispatchKeyEvent(ViewGroup.java:1112)
at android.view.ViewGroup.dispatchKeyEvent(ViewGroup.java:1112)
at android.widget.TabHost.dispatchKeyEvent(TabHost.java:297)
at android.view.ViewGroup.dispatchKeyEvent(ViewGroup.java:1112)
at android.view.ViewGroup.dispatchKeyEvent(ViewGroup.java:1112)
at android.view.ViewGroup.dispatchKeyEvent(ViewGroup.java:1112)
at com.android.internal.policy.impl.PhoneWindow$DecorView.superDispatchKeyEvent(PhoneWindow.java:1855)
at com.android.internal.policy.impl.PhoneWindow.superDispatchKeyEvent(PhoneWindow.java:1277)
at android.app.Activity.dispatchKeyEvent(Activity.java:2269)
at com.android.internal.policy.impl.PhoneWindow$DecorView.dispatchKeyEvent(PhoneWindow.java:1803)
at android.view.ViewRoot.deliverKeyEventPostIme(ViewRoot.java:2880)
at android.view.ViewRoot.handleFinishedEvent(ViewRoot.java:2853)
at android.view.ViewRoot.handleMessage(ViewRoot.java:2028)
at android.os.Handler.dispatchMessage(Handler.java:99)
at android.os.Looper.loop(Looper.java:132)
at android.app.ActivityThread.main(ActivityThread.java:4028)
at java.lang.reflect.Method.invokeNative(Native Method)
at java.lang.reflect.Method.invoke(Method.java:491)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:844)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:602)
at dalvik.system.NativeStart.main(Native Method)

Apparently it has something to do with a FragmentManager, which I don't use. The stacktrace doesn't show any of my own classes, so I have no idea where this exception occurs and how to prevent it.

For the record: I have a tabhost, and in each tab there is a ActivityGroup switching between Activities.

Answer 1

In regards to @Anthonyeef great answer, here is a sample code in Java:

private boolean shouldShowFragmentInOnResume;

private void someMethodThatShowsTheFragment() {

    if (this.getLifecycle().getCurrentState().isAtLeast(Lifecycle.State.RESUMED)) {
        showFragment();
    } else {
        shouldShowFragmentInOnResume = true;
    }
}

private void showFragment() {
    //Your code here
}

@Override
protected void onResume() {
    super.onResume();

    if (shouldShowFragmentInOnResume) {
        shouldShowFragmentInOnResume = false;
        showFragment();
    }
}

Answer 2

I have also experienced this issue and problem occurs every time when context of your FragmentActivity gets changed (e.g. Screen orientation is changed, etc.). So the best fix for it is to update context from your FragmentActivity.

Answer 3

Please check my answer here. Basically I just had to :

@Override
protected void onSaveInstanceState(Bundle outState) {
    //No call for super(). Bug on API Level > 11.
}

Don't make the call to super() on the saveInstanceState method. This was messing things up...

This is a known bug in the support package.

If you need to save the instance and add something to your outState Bundle you can use the following:

@Override
protected void onSaveInstanceState(Bundle outState) {
    outState.putString("WORKAROUND_FOR_BUG_19917_KEY", "WORKAROUND_FOR_BUG_19917_VALUE");
    super.onSaveInstanceState(outState);
}

In the end the proper solution was (as seen in the comments) to use :

transaction.commitAllowingStateLoss();

when adding or performing the FragmentTransaction that was causing the Exception.

Answer 4

There are many related problems with a similar error message. Check the second line of this particular stack trace. This exception is specifically related to the call to FragmentManagerImpl.popBackStackImmediate.

This method call, like popBackStack, will always fail with IllegalArgumentException if the session state has already been saved. Check the source. There is nothing you can do to stop this exception being thrown.

• Removing the call to super.onSaveInstanceState will not help.
• Creating the Fragment with commitAllowingStateLoss will not help.

Here's how I observed the problem:

• There's a form with a submit button.
• When the button is clicked a dialog is created and an async process starts.
• The user clicks the home key before the process is finished - onSaveInstanceState is called.
• The process completes, a callback is made and popBackStackImmediate is attempted.
• IllegalStateException is thrown.

Here's what I did to solve it:

As it is not possible to avoid the IllegalStateException in the callback, catch & ignore it.

try {
    activity.getSupportFragmentManager().popBackStackImmediate(name);
} catch (IllegalStateException ignored) {
    // There's no way to avoid getting this if saveInstanceState has already been called.
}

This is enough to stop the app from crashing. But now the user will restore the app and see that the button they thought they'd pressed hasn't been pressed at all (they think). The form fragment is still showing!

To fix this, when the dialog is created, make some state to indicate the process has started.

progressDialog.show(fragmentManager, TAG);
submitPressed = true;

And save this state in the bundle.

@Override
public void onSaveInstanceState(Bundle outState) {
    ...
    outState.putBoolean(SUBMIT_PRESSED, submitPressed);
}

Don't forget to load it back again in onViewCreated

Then, when resuming, rollback the fragments if submit was previously attempted. This prevents the user from coming back to what seems like an un-submitted form.

@Override
public void onResume() {
    super.onResume();
    if (submitPressed) {
        // no need to try-catch this, because we are not in a callback
        activity.getSupportFragmentManager().popBackStackImmediate(name);
        submitPressed = false;
    }
}

Answer 5

Whenever you are trying to load a fragment in your activity make sure that activity is in resume and not going to pause state.In pause state you may end up losing commit operation that is done.

You can use transaction.commitAllowingStateLoss() instead of transaction.commit() to load fragment

or

Create a boolean and check if activity is not going to onpause

@Override
public void onResume() {
    super.onResume();
    mIsResumed = true;
}

@Override
public void onPause() {
    mIsResumed = false;
    super.onPause();
}

then while loading fragment check

if(mIsResumed){
//load the your fragment
}

Answer 6

Check if the activity isFinishing() before showing the fragment and pay attention to commitAllowingStateLoss().

Example:

if(!isFinishing()) {
FragmentManager fm = getSupportFragmentManager();
            FragmentTransaction ft = fm.beginTransaction();
            DummyFragment dummyFragment = DummyFragment.newInstance();
            ft.add(R.id.dummy_fragment_layout, dummyFragment);
            ft.commitAllowingStateLoss();
}