Why does wide file-stream in C++ narrow written da

Question

Honestly, I just don't get the following design decision in C++ Standard library. When writing wide characters to a file, the wofstream converts wchar_t into char characters:

#include <fstream>
#include <string>

int main()
{
    using namespace std;

    wstring someString = L"Hello StackOverflow!";
    wofstream file(L"Test.txt");

    file << someString; // the output file will consist of ASCII characters!
}

I am aware that this has to do with the standard codecvt. There is codecvt for utf8 in Boost. Also, there is a codecvt for utf16 by Martin York here on SO. The question is why the standard codecvt converts wide-characters? why not write the characters as they are!

Also, are we gonna get real unicode streams with C++0x or am I missing something here?

Answer 1

For your first question, this is my guess.

The IOStreams library was constructed under a couple of premises regarding encodings. For converting between Unicode and other not so usual encodings, for example, it's assumed that.

• Inside your program, you should use a (fixed-width) wide-character encoding.
• Only external storage should use (variable-width) multibyte encodings.

I believe that is the reason for the existence of the two template specializations of std::codecvt. One that maps between char types (maybe you're simply working with ASCII) and another that maps between wchar_t (internal to your program) and char (external devices). So whenever you need to perform a conversion to a multibyte encoding you should do it byte-by-byte. Notice that you can write a facet that handles encoding state when you read/write each byte from/to the multibyte encoding.

Thinking this way the behavior of the C++ standard is understandable. After all, you're using wide-character ASCII encoded (assuming this is the default on your platform and you did not switch locales) strings. The "natural" conversion would be to convert each wide-character ASCII character to a ordinary (in this case, one char) ASCII character. (The conversion exists and is straightforward.)

By the way, I'm not sure if you know, but you can avoid this by creating a facet that returns noconv for the conversions. Then, you would have your file with wide-characters.

Answer 2

A very partial answer for the first question: A file is a sequence of bytes so, when dealing with wchar_t's, at least some conversion between wchar_t and char must occur. Making this conversion "intelligently" requires knowledge of the character encodings, so this is why this conversion is allowed to be locale-dependent, by virtue of using a facet in the stream's locale.

Then, the question is how that conversion should be made in the only locale required by the standard: the "classic" one. There is no "right" answer for that, and the standard is thus very vague about it. I understand from your question that you assume that blindly casting (or memcpy()-ing) between wchar_t[] and char[] would have been a good way. This is not unreasonable, and is in fact what is (or at least was) done in some implementations.

Another POV would be that, since a codecvt is a locale facet, it is reasonable to expect that the conversion is made using the "locale's encoding" (I'm handwavy here, as the concept is pretty fuzzy). For example, one would expect a Turkish locale to use ISO-8859-9, or a Japanese on to use Shift JIS. By similarity, the "classic" locale would convert to this "locale's encoding". Apparently, Microsoft chose to simply trim (which leads to IS-8859-1 if we assuming that wchar_t represents UTF-16 and that we stay in the basic multilingual plane), while the Linux implementation I know about decided stick to ASCII.

For your second question:

Also, are we gonna get real unicode streams with C++0x or am I missing something here?

In the [locale.codecvt] section of n2857 (the latest C++0x draft I have at hand), one can read:

The specialization codecvt<char16_t, char, mbstate_t> converts between the UTF-16 and UTF-8 encodings schemes, and the specialization codecvt <char32_t, char, mbstate_t> converts between the UTF-32 and UTF-8 encodings schemes. codecvt<wchar_t,char,mbstate_t> converts between the native character sets for narrow and wide characters.

In the [locale.stdcvt] section, we find:

For the facet codecvt_utf8: — The facet shall convert between UTF-8 multibyte sequences and UCS2 or UCS4 (depending on the size of Elem) within the program. [...]

For the facet codecvt_utf16: — The facet shall convert between UTF-16 multibyte sequences and UCS2 or UCS4 (depending on the size of Elem) within the program. [...]

For the facet codecvt_utf8_utf16: — The facet shall convert between UTF-8 multibyte sequences and UTF-16 (one or two 16-bit codes) within the program.

So I guess that this means "yes", but you'd have to be more precise about what you mean by "real unicode streams" to be sure.

Answer 3

The model used by C++ for charsets is inherited from C, and so dates back to at least 1989.

Two main points:

• IO is done in term of char.
• it is the job of the locale to determine how wide chars are serialized
• the default locale (named "C") is very minimal (I don't remember the constraints from the standard, here it is able to handle only 7-bit ASCII as narrow and wide character set).
• there is an environment determined locale named ""

So to get anything, you have to set the locale.

If I use the simple program

#include <locale>
#include <fstream>
#include <ostream>
#include <iostream>

int main()
{
    wchar_t c = 0x00FF;
    std::locale::global(std::locale(""));
    std::wofstream os("test.dat");
    os << c << std::endl;
    if (!os) {
        std::cout << "Output failed\n";
    }
}

which use the environment locale and output the wide character of code 0x00FF to a file. If I ask to use the "C" locale, I get

$ env LC_ALL=C ./a.out
Output failed

the locale has been unable to handle the wide character and we get notified of the problem as the IO failed. If I run ask an UTF-8 locale, I get

$ env LC_ALL=en_US.utf8 ./a.out
$ od -t x1 test.dat
0000000 c3 bf 0a
0000003

(od -t x1 just dump the file represented in hex), exactly what I expect for an UTF-8 encoded file.

Answer 4

Check this out: Class basic_filebuf

You can alter the default behavior by setting a wide char buffer, using pubsetbuf. Once you did that, the output will be wchar_t and not char.

In other words for your example you will have:

wofstream file(L"Test.txt", ios_base::binary); //binary is important to set!  
wchar_t buffer[128];  
file.rdbuf()->pubsetbuf(buffer, 128);  
file.put(0xFEFF); //this is the BOM flag, UTF16 needs this, but mirosoft's UNICODE doesn't, so you can skip this line, if any.  
file << someString; // the output file will consist of unicode characters! without the call to pubsetbuf, the out file will be ANSI (current regional settings)  

Answer 5

I don't know about wofstream. But C++0x will include new distict character types (char16_t, char32_t) of guaranteed width and signedness (unsigned) which can be portably used for UTF-8, UTF-16 and UTF-32. In addition, there will be new string literals (u"Hello!" for an UTF-16 coded string literal, for example)

Check out the most recent C++0x draft (N2960).