Writing white-space delimited text to be human rea

2019-05-09 09:13发布

I have a list of lists that looks something like this:

data = [['seq1', 'ACTAGACCCTAG'],
        ['sequence287653', 'ACTAGNACTGGG'],
        ['s9', 'ACTAGAAACTAG']]

I write the information to a file like this:

for i in data:
    for j in i:
        file.write('\t')
        file.write(j)
    file.write('\n')

The output looks like this:

seq1   ACTAGACCCTAG  
sequence287653   ACTAGNACTGGG  
s9   ACTAGAAACTAG  

The columns don't line up neatly because of variation in the length of the first element in each internal list. How can I write appropriate amounts of whitespace between the first and second elements to make the second column line up for human readability?

3条回答
干净又极端
2楼-- · 2019-05-09 09:20
data = [['seq1', 'ACTAGACCCTAG'],
        ['sequence287653', 'ACTAGNACTGGG'],
        ['s9', 'ACTAGAAACTAG']]
with open('myfile.txt', 'w') as file:
    file.write('\n'.join('%-15s %s' % (i,j) for i,j in data) )

for me is even clearer than expression with loop

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孤傲高冷的网名
3楼-- · 2019-05-09 09:26

You need a format string:

for i,j in data:
    file.write('%-15s %s\n' % (i,j))

%-15s means left justify a 15-space field for a string. Here's the output:

seq1            ACTAGACCCTAG
sequence287653  ACTAGNACTGGG
s9              ACTAGAAACTAG
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Rolldiameter
4楼-- · 2019-05-09 09:37

"%10s" % obj will ensure minimum 10 spaces with the string representation of obj aligned on the right.

"%-10s" % obj does the same, but aligns to the left.

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