How to extract table names and column names from s

2019-05-09 07:47发布

So let assume we have such simple query:

Select a.col1, b.col2 from tb1 as a inner join tb2 as b on tb1.col7 = tb2.col8;

The result should looks this way:

tb1 col1
tb1 col7
tb2 col2
tb2 col8

I've tried to solve this problem using some python library:

1) Even extracting only tables using sqlparse might be a huge problem. For example this official book doesn't work properly at all.

2) Using regular expression seems to be really hard to achieve.

3) But then I found this , that might help. However the problem is that I can't connect to any database and execute that query.

Any ideas?

2条回答
Summer. ? 凉城
2楼-- · 2019-05-09 08:27

I am tackling a similar problem and found a simpler solution and it seems to work well.

import re

def tables_in_query(sql_str):

    # remove the /* */ comments
    q = re.sub(r"/\*[^*]*\*+(?:[^*/][^*]*\*+)*/", "", sql_str)

    # remove whole line -- and # comments
    lines = [line for line in q.splitlines() if not re.match("^\s*(--|#)", line)]

    # remove trailing -- and # comments
    q = " ".join([re.split("--|#", line)[0] for line in lines])

    # split on blanks, parens and semicolons
    tokens = re.split(r"[\s)(;]+", q)

    # scan the tokens. if we see a FROM or JOIN, we set the get_next
    # flag, and grab the next one (unless it's SELECT).

    table = set()
    get_next = False
    for tok in tokens:
        if get_next:
            if tok.lower() not in ["", "select"]:
                table.add(tok)
            get_next = False
        get_next = tok.lower() in ["from", "join"]

    dictTables = dict()
    for table in tables:
        fields = []
        for token in tokens:
            if token.startswith(table):
                if token != table:
                    fields.append(token)
        if len(list(set(fields))) >= 1:
        dictTables[table] = list(set(fields))
    return dictTables

code adapted from https://grisha.org/blog/2016/11/14/table-names-from-sql/

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Anthone
3楼-- · 2019-05-09 08:44

Really, this is no easy task. You could use a lexer (ply in this example) and define several rules to get several tokens out of a string. The following code defines these rules for the different parts of your SQL string and puts them back together as there could be aliases in the input string. As a result, you get a dictionary (result) with the different tablenames as key.

import ply.lex as lex, re

tokens = (
    "TABLE",
    "JOIN",
    "COLUMN",
    "TRASH"
)

tables = {"tables": {}, "alias": {}}
columns = []

t_TRASH = r"Select|on|=|;|\s+|,|\t|\r"

def t_TABLE(t):
    r"from\s(\w+)\sas\s(\w+)"

    regex = re.compile(t_TABLE.__doc__)
    m = regex.search(t.value)
    if m is not None:
        tbl = m.group(1)
        alias = m.group(2)
        tables["tables"][tbl] = ""
        tables["alias"][alias] = tbl

    return t

def t_JOIN(t):
    r"inner\s+join\s+(\w+)\s+as\s+(\w+)"

    regex = re.compile(t_JOIN.__doc__)
    m = regex.search(t.value)
    if m is not None:
        tbl = m.group(1)
        alias = m.group(2)
        tables["tables"][tbl] = ""
        tables["alias"][alias] = tbl
    return t

def t_COLUMN(t):
    r"(\w+\.\w+)"

    regex = re.compile(t_COLUMN.__doc__)
    m = regex.search(t.value)
    if m is not None:
        t.value = m.group(1)
        columns.append(t.value)
    return t

def t_error(t):
    raise TypeError("Unknown text '%s'" % (t.value,))
    t.lexer.skip(len(t.value))

# here is where the magic starts
def mylex(inp):
    lexer = lex.lex()
    lexer.input(inp)

    for token in lexer:
        pass

    result = {}
    for col in columns:
        tbl, c = col.split('.')
        if tbl in tables["alias"].keys():
            key = tables["alias"][tbl]
        else:
            key = tbl

        if key in result:
            result[key].append(c)
        else:
            result[key] = list()
            result[key].append(c)

    print result
    # {'tb1': ['col1', 'col7'], 'tb2': ['col2', 'col8']}    

string = "Select a.col1, b.col2 from tb1 as a inner join tb2 as b on tb1.col7 = tb2.col8;"
mylex(string)
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