MbUnit: The most elegant way to compare doubles?

2019-05-08 06:28发布

The code

Assert.AreEqual (9.97320998018748d, observerPosition.CenterLongitude);

produces

Expected Value & Actual Value : 9.97320998018748
Remark : Both values look the same when formatted but they 
are distinct instances.

What is the most elegant way to compare two doubles for equality in MbUnit 3.0? I know I could round them up myself, but is there some MbUnit construct for this?

UPDATE: I consider my current "workaround" to be non-elegant:

Assert.LessThan(
   Math.Abs(9.97320998018748d - observerPosition.CenterLongitude),
   0.0000001);

标签: mbunit gallio
1条回答
Emotional °昔
2楼-- · 2019-05-08 06:42

AreApproximatelyEqual seems to be the "MbUnit construct for this":

Verifies that an actual value approximately equals some expected value to within a specified delta.

This seems to be similar to Assert.AreEqual(double expected, double actual, double delta)

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