Which is the correct way to encode escape characte

Question

I think I'm going crazy with Python's unicode strings. I'm trying to encode escape characters in a Unicode string without escaping actual Unicode characters. I'm getting this:

In [14]: a = u"Example\n"

In [15]: b = u"Пример\n"

In [16]: print a
Example


In [17]: print b
Пример


In [18]: print a.encode('unicode_escape')
Example\n

In [19]: print b.encode('unicode_escape')
\u041f\u0440\u0438\u043c\u0435\u0440\n

while I desperately need (English example works as I want, obviously):

In [18]: print a.encode('unicode_escape')
Example\n

In [19]: print b.encode('unicode_escape')
Пример\n

What should I do, short of moving to Python 3?

PS: As pointed out below, I'm actually seeking to escape control characters. Whether I need more than just those will have to be seen.

Answer 1

The method .encode returns a byte-string (type str in Python 2), so it cannot return unicode characters.

But as there are only few \ - sequences you can easily .replace them manually. See http://docs.python.org/reference/lexical_analysis.html#string-literals for a complete list.

Answer 2

First let's correct the terminology. What you're trying to do is replace "control characters" with an equivalent "escape sequence".

I haven't been able to find any built-in method to do this, and nobody has yet posted one. Fortunately it's not a hard function to write.

control_chars = [unichr(c) for c in range(0x20)] # you may extend this as required

def control_escape(s):
    chars = []
    for c in s:
        if c in control_chars:
            chars.append(c.encode('unicode_escape'))
        else:
            chars.append(c)
    return u''.join(chars)

Or the slightly less readable one-liner version:

def control_escape2(s):
    return u''.join([c.encode('unicode_escape') if c in control_chars else c for c in s])

Answer 3

Backslash escaping ascii control characters in the middle of unicode data is definitely a useful thing to try to accomplish. But it's not just escaping them, it's properly unescaping them when you want the actual character data back.

There should be a way to do this in the python stdlib, but there is not. I filed a bug report: http://bugs.python.org/issue18679

but in the mean time, here's a work around using translate and hackery:

tm = dict((k, repr(chr(k))[1:-1]) for k in range(32))
tm[0] = r'\0'
tm[7] = r'\a'
tm[8] = r'\b'
tm[11] = r'\v'
tm[12] = r'\f'
tm[ord('\\')] = '\\\\'

b = u"Пример\n"
c = b.translate(tm)
print(c) ## results in: Пример\n

All the non-backslash-single-letter control characters will be escaped with the \x## sequence, but if you need something different done with those, your translation matrix can do that. This approach is not lossy though, so it works for me.

But getting it back out is hacky too because you can't just translate character sequences back into single characters using translate.

d = c.encode('latin1', 'backslashreplace').decode('unicode_escape')
print(d) ## result in Пример with trailing newline character

you actually have to encode the characters that map to bytes individually using latin1 while backslash escaping unicode characters that latin1 doesn't know about so that the unicode_escape codec can handle reassembling everything the right way.

UPDATE:

So I had a case where I needed this to work in both python2.7 and python3.3. Here's what I did (buried in a _compat.py module):

if isinstance(b"", str):                                                        
    byte_types = (str, bytes, bytearray)                                        
    text_types = (unicode, )                                                    
    def uton(x): return x.encode('utf-8', 'surrogateescape')                    
    def ntob(x): return x                                                       
    def ntou(x): return x.decode('utf-8', 'surrogateescape')                    
    def bton(x): return x
else:                                                                           
    byte_types = (bytes, bytearray)                                             
    text_types = (str, )                                                        
    def uton(x): return x                                                       
    def ntob(x): return x.encode('utf-8', 'surrogateescape')                    
    def ntou(x): return x                                                       
    def bton(x): return x.decode('utf-8', 'surrogateescape')    

escape_tm = dict((k, ntou(repr(chr(k))[1:-1])) for k in range(32))              
escape_tm[0] = u'\0'                                                            
escape_tm[7] = u'\a'                                                            
escape_tm[8] = u'\b'                                                            
escape_tm[11] = u'\v'                                                           
escape_tm[12] = u'\f'                                                           
escape_tm[ord('\\')] = u'\\\\'

def escape_control(s):                                                          
    if isinstance(s, text_types):                                               
        return s.translate(escape_tm)
    else:
        return s.decode('utf-8', 'surrogateescape').translate(escape_tm).encode('utf-8', 'surrogateescape')

def unescape_control(s):                                                        
    if isinstance(s, text_types):                                               
        return s.encode('latin1', 'backslashreplace').decode('unicode_escape')
    else:                                                                       
        return s.decode('utf-8', 'surrogateescape').encode('latin1', 'backslashreplace').decode('unicode_escape').encode('utf-8', 'surrogateescape')

Answer 4

.encode('unicode_escape') returns a byte string. You probably want to escape the control characters directly in the Unicode string:

# coding: utf8
import re

def esc(m):
    return u'\\x{:02x}'.format(ord(m.group(0)))

s = u'\r\t\b马克\n'

# Match control characters 0-31.
# Use DOTALL option to match end-of-line control characters as well.
print re.sub(ur'(?s)[\x00-\x1f]',esc,s)

Output:

\x0d\x09\x08马克\x0a

Note there are other Unicode control characters beyond 0-31, so you may need something more like:

# coding: utf8
import re
import unicodedata as ud

def esc(m):
    c = m.group(0)
    if ud.category(c).startswith('C'):
        return u'\\u{:04x}'.format(ord(c))
    return c

s = u'\rMark\t\b马克\n'

# Match ALL characters so the replacement function
# can test the category.  Not very efficient if the string is long.
print re.sub(ur'(?s).',esc,s)

Output:

\u000dMark\u0009\u0008马克\u000a

You may want finer control of what is considered a control character. There are a number of categories. You could build a regular expression matching a specific type with:

import sys
import re
import unicodedata as ud

# Generate a regular expression that matches any Cc category Unicode character.
Cc_CODES = u'(?s)[' + re.escape(u''.join(unichr(n) for n in range(sys.maxunicode+1) if ud.category(unichr(n)) == 'Cc')) + u']'