Getting SQL Exception while using prepared stateme

2019-05-07 04:19发布

StringBuilder sqlQry = new StringBuilder();
sqlQry.append("SELECT LIB, PATH")
.append(" FROM OBJ")
.append(" INNER JOIN SRC ON SRC.MBR = OBJ.LOBJ")
.append(" WHERE  TYPE = '*PGM'")
.append(" AND SRC.PATH LIKE '").append("?").append("%'");

PreparedStatement ps = accssConn.prepareStatement(sqlQry.toString());
ps.setString(1, path);

rs = ps.executeQuery();

Hi All, I am getting following exception

[jcc][10145][10844][3.63.123] Invalid parameter 1: Parameter index is out of range. ERRORCODE=-4461, SQLSTATE=42815

column limit is 255 and path is = "C:\Documents and Settings\xyz\Desktop\xyzs" and it is run fine with statement.So , what is the reason that it is throwing exception in prepared statement.

2条回答
劫难
2楼-- · 2019-05-07 04:40
StringBuilder sqlQry = new StringBuilder();

sqlQry.append("SELECT LIB, PATH")
.append(" FROM OBJ")
.append(" INNER JOIN SRC ON SRC.MBR = OBJ.LOBJ")
.append(" WHERE  TYPE = '*PGM'")
.append(" AND SRC.PATH LIKE ").append("?");

PreparedStatement ps = accssConn.prepareStatement(sqlQry.toString());

ps.setString(1, path + "%");
查看更多
放荡不羁爱自由
3楼-- · 2019-05-07 04:47

Check your single quotes I think one of them is missing closing quote. Also try changing your single quotes to double quotes and escaping them like so \"*PGM\"

查看更多
登录 后发表回答