How to get a HTTP POST request body as a Java Stri

2019-05-06 17:55发布

The getRequestBody method of the HttpExchange object returns an InputStream. There is still much work for correctly read the "Body". Is it a Java library + object + method that goes one more step ahead and returns the body (at the server side) as a ready-to-use Java String?

Thanks!

标签: java http post
4条回答
叛逆
2楼-- · 2019-05-06 18:05

You can use Commons IO's org.apache.commons.io.IOUtils.toString(InputStream, String) to do this in one line. (It might not work with HTTP keep-alive though)

Edit:

If you want to go straight to JSON, there are a bunch of Web Service stacks that will do the unmarshalling for you. Try

Spring: http://www.cribbstechnologies.com/2011/04/08/spring-mvc-ajax-web-services-part-2-attack-of-the-json-post/

CXF / JAX-RS: http://cxf.apache.org/docs/jax-rs-data-bindings.html#JAX-RSDataBindings-JSONsupport

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淡お忘
3楼-- · 2019-05-06 18:18

If you are using Spring MVC, you can use the @RequestBody annotation on a method parameter which is of type String. For example.

@RequestMapping(value = "/something", method = RequestMethod.POST)
public void doSomething(@RequestBody String requestBodyString) {
    // does something..
}
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家丑人穷心不美
4楼-- · 2019-05-06 18:26

Did you try this ?

 InputStreamReader isr =  new InputStreamReader(exchange.getRequestBody(),"utf-8");
 BufferedReader br = new BufferedReader(isr);
 String value = br.readLine();
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我欲成王,谁敢阻挡
5楼-- · 2019-05-06 18:27
InputStreamReader isr =  new InputStreamReader(t.getRequestBody(),"utf-8");
BufferedReader br = new BufferedReader(isr);

// From now on, the right way of moving from bytes to utf-8 characters:

int b;
StringBuilder buf = new StringBuilder(512);
while ((b = br.read()) != -1) {
    buf.append((char) b);
}

br.close();
isr.close();

// The resulting string is: buf.toString()
// and the number of BYTES (not utf-8 characters) from the body is: buf.length()
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