If I were to wanted to parameterize creating an object, I could of course make a function which called new on a particular class and passed out a pointer. I am wondering if it's possible to skip that step and pass a function pointer to the new
operator itself.
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boost::lambda provides function wrappers for
new
anddelete
. These can be used to easily convert annew
call into a function object.operator new
(as well as the other flavours) takes care of allocating memory but does not construct objects. In fact its return type isvoid*
. What constructs an object is a new expression, which is part of the language and not a function. So it's not possible to form a pointer or reference to it; it's as meaningless as forming a reference toreturn
.