suppose I have a numeric vector like:
x <- c(1.0, 2.5, 3.0)
and data.frame:
df<-data.frame(key=c(0.5,1.0,1.5,2.0,2.5,3.0),
value=c(-1.187,0.095,-0.142,-0.818,-0.734,0.511))
df
key value
1 0.5 -1.187
2 1.0 0.095
3 1.5 -0.142
4 2.0 -0.818
5 2.5 -0.734
6 3.0 0.511
I want to extract all the rows in df$key that have the same values equal to x, with result like:
df.x$value
[1] 0.095 -0.734 0.511
Is there an efficient way to do this please? I've tried data.frame, hash package and data.table, all with no success. Thanks for help!
Thanks guys. I actually tried similar thing but got df$key and x reversed. Is it possible to do this with the hash() function (in the 'hash' package)? I see hash can do things like:
h <- hash( keys=letters, values=1:26 )
h$a # 1
h$foo <- "bar"
h[ "foo" ]
h[[ "foo" ]]
z <- letters[3:5]
h[z]
<hash> containing 3 key-value pair(s).
c : 3
d : 4
e : 5
But seems like it doesn't take an array in its key chain, such as:
h[[z]]
Error in h[[z]] : wrong arguments for subsetting an environment
but I need the values only as in a vector rather than a hash. Otherwise, it would be perfect so that we can get rid of data.frame by using some 'real' hash concept.
Try,
Using an OR
|
condition you may modify it in such a way that your vector may occur in either of your columns. General tip: also have a look atwhich
.Have you tried testing the valued of df$key that are in x and extracting the value in the value column? I only say this out loud because StackOverflow doesnt like oneline answers:
BIG WARNING - comparisons with floating point numbers with == can be a bad idea - read R FAQ 7.31 for more info.