Change member-typedef depending on template parame

Question

I have this problem here that I can’t figure out how to solve. I want a template class that takes an integer as template parameter and sets the template parameters for another class accordingly:

template <int T>
class Solver
{

  public:

    #if T <= 24
      typedef MyMatrix<float> Matrix;
    #else if T <= 53
      typedef MyMatrix<double> Matrix;
    #else
      typedef MyMatrix<mpreal> Matrix;
    #endif

    Matrix create();

};

And then calling it like this:

Solver<53>::Matrix m = Solver<53>::create();

How can I do something like this? At the moment with the code above, the compiler complaints that it doesn't know "Matrix", so I'm not sure if you can use the preprocessor on template parameters.

Answer 1

No, you can't use the preprocessor on template parameters.

The preprocessor is just doing very simple string processing on your input source. It has no glue about types and I think it is run as the very first step while first processing the file and collecting all the includes. Templates are something the compiler itself takes care of. At this point the preprocessor has finished already.

A similar question has been asked here: Use a template parameter in a preprocessor directive?

Answer 2

You can use std::conditional for this, although whether you should be doing this in the first place is another kettle of fish:

template<int T>
class Solver
{
  std::conditional_t<
    T <= 24,
    MyMatrix<float>,
    std::conditional_t<
      T <= 53,
      MyMatrix<double>,
      MyMatrix<mpreal>
    >
  > Matrix;
};

You'll need to use std::conditional and ::type instead of conditional_t if your compiler doesn't support it.

Answer 3

INTRODUCTION

Since you'd like S<N>::Matrix to yield a different type depending on the N passed, you will need to use some sort of meta template programming. The question is currently tagged with preprocessor, and the snippet explicitly tries to use it; but that is of little to no use in this case.

When the code is being preprocessed N is nothing more than a name, it hasn't got a value; yet.

---

Solution

The description mentiones if, if ... else, and else; and we are dealing with types.. looking through <type_traits> it seems like std::conditional would be a perfect match!

std::conditional<condition, type-if-true, type-if-false>::type;

^{Note: Depending on whether the expression found in condition yields true, or false, ::type will be a typedef for either type-if-true, or type-if-false.}

---

Let's write a sample implementation:

#include <type_traits>

template <int N>
class Solver
{
  public:
    typedef typename std::conditional<
      /*    */ (N <= 24),
      /* y? */ MyMatrix<float>,
      /* n? */ typename std::conditional<(N <= 53), MyMatrix<double>, MyMatrix<mpreal>>::type
    >::type matrix_type;

  ...
};

int main () {
  Solver<53>::matrix_type a; // Matrix<double>
  Solver<10>::matrix_type b; // Matrix<float>
  Solver<99>::matrix_type c; // Matrix<mpreal>
}