What is the minimal difference in RGB color values

2019-04-30 04:21发布

I was amazed when I found that Mathematica gives True for the following code (on 32 bit Windows XP with Mathematica 8.0.1):

Rasterize[Graphics[{RGBColor[0, 0, 0], Disk[]}]] === 
 Rasterize[Graphics[{RGBColor[0, 0, 1/257], Disk[]}]]

What is the minimal difference in RGB color values which Mathematica renders and exports as different colors? Is it machine-dependent?

3条回答
【Aperson】
2楼-- · 2019-04-30 05:03

Looks like Rasterize rounds each pixel's R G B channels to the closest 8bit value (to the closest 1/256).

image = Image[{{{0, 0, .2/256}, {0, 0, .7/256}, {0, 0, 1.2/256}, {0, 
     0, 1.7/256}}}, ImageSize -> 4]
ImageData@image
Rasterize@image
ImageData@Rasterize@image

enter image description here

So the minimal difference, rasterizing into different colors should be around 0.000000000000000000000000000...

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劫难
3楼-- · 2019-04-30 05:20

Guilty party here is Rasterize, which chops off color precision. Get help on ImageType[] to see that Mathematica actually recognizes other bit depths, but Rasterize[] vandalizes anything beyond Byte.

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手持菜刀,她持情操
4楼-- · 2019-04-30 05:26

I believe this behaviour is machine dependent, but I do not know how exactly it depends on the OS. On my machine, it evaluates to True only when the denominator is 511.

n = 257; 
While[(Rasterize[Graphics[{RGBColor[0, 0, 0], Disk[]}]] === 
    Rasterize[Graphics[{RGBColor[0, 0, 1/n], Disk[]}]]) != True, 
 n++]; 
Print@n

Out[1]=511

There is a difference between the two images for n<511

p1 = ImageData@Rasterize[Graphics[{RGBColor[0, 0, 0], Disk[]}]];
p2 = ImageData@Rasterize[Graphics[{RGBColor[0, 0, 1/257], Disk[]}]];
ArrayPlot[p1 - p2]

enter image description here

This difference is constant all the way through n=510 and is equal to 1/255.

Max[p2 - p1] === N[1/255]
Out[1]=True
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