I know that it is possible for a function to return multiple values in Python. What I would like to do is return each element in a list as a separate return value. This could be an arbitrary number of elements, depending on user input. I am wondering if there is a pythonic way of doing so?
For example, I have a function that will return a pair of items as an array, e.g., it will return [a, b]
.
However, depending on the input given, the function may produce multiple pairs, which will result in the function returning [[a, b], [c, d], [e, f]]
. Instead, I would like it to return [a, b], [c, d], [e, f]
As of now, I have implemented a very shoddy function with lots of temporary variables and counts, and am looking for a cleaner suggestion.
Appreciate the help!
Check out this question: How to return multiple values from *args?
The important idea is return values, as long as they're a container, can be expanded into individual variables.
There is a yield statement which matches perfectly for this usecase.
This will return a generator which you can iterate.
Can you not just use the returned list (i.e. the list [[a, b], [c, d], [e, f]]) and extract the elements from it? Seems to meet your criteria of arbitrary number of / multiple values.
When a python function executes:
what it actually returns is the tuple
(a, b, c)
, and tuples are unpacked on assignment, so you can say:and all is well. So if you have a list
Your function can simply:
and behave like you expect:
will do the assignments as you expect.
If what you really want is for a function to return an indeterminate number of things as a sequence that you can iterate over, then you'll want to make it a generator using
yield
, but that's a different ball of wax.