public enum ReportStatus {
SUCCCEED, FAILED;
}
public class Work {
@ElementCollection
@Enumerated(EnumType.STRING)
List<ReportStatus> reportStatuses;
}
Given the following structure, I'd like to perform a query to find all the work filtered by reportStatuses. It works fine with the following hql syntax :
public List<Long> queryHQL() {
final String query = "SELECT w.id FROM Work w JOIN w.reportStatuses s WHERE s in (:rs)";
final List<ReportStatus> reportStatuses = new ArrayList<ReportStatus>();
reportStatuses.add(ReportStatus.FAILED);
return this.entityManager.createQuery(query).setParameter("rs", reportStatuses).getResultList();
}
But I'd like to use the criteria API (jpa2), and can't figure out how to do it. Here is my closest try I think :
public List<Long> query() {
final List<ReportStatus> reportStatuses = new ArrayList<ReportStatus>();
reportStatuses.add(ReportStatus.FAILED);
final CriteriaBuilder builder = this.entityManager.getCriteriaBuilder();
final CriteriaQuery<Long> criteriaQuery = builder.createQuery(Long.class);
final Root<Work> workModel = criteriaQuery.from(Work.class);
final ListJoin<Work, ReportStatus> status = workModel.joinList("reportStatuses");
final Predicate predicate = status.in(reportStatuses);
criteriaQuery.where(predicate);
criteriaQuery.select(workModel.<Long> get("id"));
return this.entityManager.createQuery(criteriaQuery).getResultList();
}
I've also tried with the hibernate criteria API, but as the jpa2 one I've failed to find the correct the syntax.
I'm confused. The call to
in(..)
returns a predicate but doesn't seem to actually enforce it (it doesn't seem to be integrated into the query—at least for me it returned all members of the root whether or not their collections intersected withreportStatuses
. The debug log shows the simple queryselect distinct work0_.id as id18_ from Work work0_
).Also, why bother putting reportStatuses in a list if the caller is only interested in those matching one value? How would you do the query w/ just using
ReportStatus.FAILED
instead of constructing a list for it?I would use following CriteriaQuery syntax for doing the same thing.
UPDATE
If you don't use Metamodel, just replace
_work.get(Work_.reportStatuses)
with_work.get("reportStatuses")
. It'll work. :)You can create this HQL.