Wait until multiple command line processes complet

2019-04-27 02:56发布

I have a need to execute many command line scripts. They are currently stored in a List. I want to run them all at the same time and proceed with the next step only after all of them have completed.

I have tried the approach that I show below, but found it lacking because the last command doesn't necessarily end last. In fact, I found that the last command can even be the first to complete. So, I believe that I need something like WaitForExit(), but which doesn't return until all executing processes have completed.

for (int i = 0; i < commands.Count; i++)
{
    string strCmdText = commands[i];
    var process = System.Diagnostics.Process.Start("CMD.exe", strCmdText);
    if (i == (commands.Count - 1))
    {
        process.WaitForExit();
    }
}
//next course of action once all the above is done

3条回答
ゆ 、 Hurt°
2楼-- · 2019-04-27 03:19

Use a Task array and wait for all of them to complete.

var tasks = new Task[commands.Count];
for (int i = 0; i < commands.Count; i++)
{
    tasks[i] = Task.Factory.StartNew(() => {
       string strCmdText = commands[i];
       var process = System.Diagnostics.Process.Start("CMD.exe", strCmdText);
       process.WaitForExit();
    });
}

Task.WaitAll(tasks);

Or, more LINQ-ishly like this:

var tasks = commands.Select(strCmdText => Task.Factory.StartNew(() => {
    var process = System.Diagnostics.Process.Start("CMD.exe", strCmdText);
    process.WaitForExit();
})).ToArray();
Task.WaitAll(tasks);
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对你真心纯属浪费
3楼-- · 2019-04-27 03:30

Since each call to Process.Start starts a new process, you can track them all separately, like so:

var processes = new List<Process>();
for (int i = 0; i < commands.Count; i++)
{
    string strCmdText = commands[i];
    processes.Add(System.Diagnostics.Process.Start("CMD.exe", strCmdText));
}

foreach(var process in processes)
{
    process.WaitForExit();
    process.Close();
}

EDIT

Process.Close() added as in the comments

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我只想做你的唯一
4楼-- · 2019-04-27 03:34

At least on Windows, you could use WaitHandle.WaitAll().

using System;
using System.Diagnostics;
using System.Threading;
using Microsoft.Win32.SafeHandles;
using static System.FormattableString;

public class ProcessWaitHandle : WaitHandle
{
    public ProcessWaitHandle(Process process) =>
        this.SafeWaitHandle = new SafeWaitHandle(process.Handle, false);
}

class Program
{
    static void Main(string[] args)
    {
        int processesCount = 42;
        var processes = new Process[processesCount];
        var waitHandles = new WaitHandle[processesCount];
        try
        {
            for (int i = 0; processesCount > i; ++i)
            {
                // exit immediately with return code i
                Process process = Process.Start(
                    "cmd.exe",
                    Invariant($"/C \"exit {i}\""));

                processes[i] = process;
                waitHandles[i] = new ProcessWaitHandle(process);
            }

            WaitHandle.WaitAll(waitHandles);
            foreach (Process p in processes)
            {
                Console.Error.WriteLine(
                    Invariant($"process with Id {p.Id} exited with code {p.ExitCode}"));
            }
        }
        finally
        {
            foreach (Process p in processes)
            {
                p?.Dispose();
            }

            foreach (WaitHandle h in waitHandles)
            {
                h?.Dispose();
            }
        }

        Console.WriteLine("Press any key to continue...");
        Console.ReadKey(false);
    }
}

This approach offers the possibility to also use other WaitAll overloads, and wait with timeouts, for example.

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