How do the digits 1101004800 correspond with the n

Question

I'm trying to learn how to modify memory locations using C++ and when messing with MineSweeper, I noticed that when the clock's value in memory was 1101004800, it was 20 seconds into the game. The digits 1101529088 correspond with 21 seconds into the game. Can someone please explain to me how to convert between those 10-digit long numbers to base-10?

Answer 1

1101004800 decimal is 0x41A00000 hex, which is the IEEE-754 representation of 20.0. 1101529088 decimal is 0x41A80000 hex, which is the IEEE-754 representation of 21.0.

Answer 2

They are using floats to represent the timer. Here is a program that converts your integers to floats:

#include <stdio.h>

int main() {
  int n = 1101004800;
  int n2 = 1101529088;

  printf("%f\n", *((float*)&n));
  printf("%f\n", *((float*)&n2));

  return 0;
}

Output:

20.000000
21.000000