Java 8 - Calling a multi argument method from Coll

2019-04-26 15:13发布

I've been using the java 8 Streams for a while. I came across a situation where I need to stream through a List and pass each element to a static method along with another argument. Is it possible in java 8?

........
String designation = "Engineer";
List<String> names = new ArrayList<>();
names.add("ABC");
names.add("DEF");
names.add("GHI");
names.stream().map(MyClass::createReport);
..........

class MyClass {
    public static void createReport(String name, String designation) {
       System.out.println(name+"\t"+designation);
    }
}

How can I pass the designation String via stream().map()?

4条回答
可以哭但决不认输i
2楼-- · 2019-04-26 15:36

You could write a curried version of the method createReport.

Curried createReport

We need to swap the order of the arguments because the designation for each name is the same. Additionly we just need to call the not curried method.

Function<String, Consumer<String>> createReportCurry = (designation) -> (name) -> {
    createReport(name, designation);
};

In Action

names.stream().forEach(createReportCurry.apply(designation))
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冷血范
3楼-- · 2019-04-26 15:41

The above answer are very good but let's try to explain why you couldn't run your code in the first place:

Your code:

names.stream().map(MyClass::createReport);names.stream().map(MyClass::createReport);

What the JVM undertands

names.stream().map(MyClass::createReport);names.stream().map(name -> MyClass.createReport(name));

Solutions use a basic lamba as @Eran or a Function as @Roman suggested.

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手持菜刀,她持情操
4楼-- · 2019-04-26 15:49

You could also use the following as an alternative:

IntStream.range(0, names.size())
         .forEach(i -> MyClass.createReport(names.get(i), names.get(i)));
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爱情/是我丢掉的垃圾
5楼-- · 2019-04-26 15:59

Use a lambda expression:

names.stream().map(name -> MyClass.createReport(name,designation))...
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