Not quite sure of the best title but I will explain what I am asking as best I can. Assume I have the following file:
MyCustomClass.php
<?php
namespace MyNamespace;
use FooNamespace\FooClass;
use BarNamespace\BarClass as Bar;
use BazNamespace\BazClass as BazSpecial;
class MyCustomClass {
protected $someDependencies = [];
public function __construct(FooClass $foo, Bar $bar) {
$someDependencies[] = $foo;
$someDependencies[] = $bar;
}
}
Now if I were to use reflection, I could get the fully qualified class names from the type hints in the construct.
However, I would recieve FooNamespace\FooClass
and BarNamespace\BarClass
. Not, FooNamespace\FooClass
and BarNamespace\Bar
. I would also get no reference to BazNamespace\BazClass
.
Basically, my question is: How can I get the fully qualified names from MyCustomClass.php
while only knowing FooClass
, Bar
, and, BazSpecial
?
I do not want to use a file parser as this will eat performance. I want to be able to do something like:
$class = new ReflectionClass('MyCustomClass');
...
$class->getUsedClass('FooClass'); // FooNamespace\FooClass
$class->getUsedClass('Bar'); // BarNamespace\BarClass
$class->getUsedClass('BazSpecial'); // BazNamespace\BazClass
How would I go about doing this?
Seeing as no one has answered, I assume there is not an easy way to achieve this. I have therefore created my own class called
ExtendedReflectionClass
which achieves what I need.I have created a gist with the class file and a readme, which is at the bottom so get scrolling!.
ExtendedReflectionClass
Usage example:
I use the TokenFinderTool for that.
Basically, it uses tokens to extract the use statements.
As far as I know, \Reflection objects in php unfortunately don't have such a method yet.
The code below extracts the use import statements from a file, using the TokenFinder tool.
Will output:
Note: if you have a class name only, you can use this snippet instead: