When converting a project to use ARC what does “sw

Question

When converting a project to use ARC what does "switch case is in protected scope" mean? I am converting a project to use ARC, using Xcode 4 Edit -> Refactor -> Convert to Objective-C ARC... One of the errors I get is "switch case is in protected scope" on "some" of the switches in a switch case.

Edit, Here is the code:

the ERROR is marked on the "default" case:

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *CellIdentifier = @"";
    UITableViewCell *cell ;
    switch (tableView.tag) {
        case 1:
            CellIdentifier = @"CellAuthor";
            cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
            if (cell == nil) {
                cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];
        }
        cell.textLabel.text = [[prefQueries objectAtIndex:[indexPath row]] valueForKey:@"queryString"];
        break;
    case 2:
        CellIdentifier = @"CellJournal";
        cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
        if (cell == nil) {
            cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];
        }
        cell.textLabel.text = [[prefJournals objectAtIndex:[indexPath row]] valueForKey:@"name"];

        NSData * icon = [[prefJournals objectAtIndex:[indexPath row]] valueForKey:@"icon"];
        if (!icon) {
            icon = UIImagePNGRepresentation([UIImage imageNamed:@"blank72"]);
        }
        cell.imageView.image = [UIImage imageWithData:icon];

        break;

    default:
        CellIdentifier = @"Cell";
        cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
        if (cell == nil) {
            initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease];
            cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];
            }
        break;
    }


    return cell;
}

Answer 1

Declare the variables outside the switch, then instantiate them inside the case. That worked perfectly for me using Xcode 6.2

Answer 2

There are 2 easy ways to solve this issue:

• You are probably declaring variables. Move the declaration of the variables outside the switch statement
• Put the whole case block in between curly brackets {}

The compiler can not calculate the code line when the variables are to be released. Causing this error.

Answer 3

Surround each case itself with braces {}. That should fix the issue (it did for me in one of my projects).

Answer 4

Surround with braces {} the code between the case statement and the break in each case. It worked on my code.

Answer 5

Before:

    case 2:
        NSDate *from = [NSDate dateWithTimeIntervalSince1970:1388552400];
        [self refreshContents:from toDate:[NSDate date]];
        break;

I moved NSDate definition before switch, and it fixed the compile problem:

NSDate *from;  /* <----------- */
switch (index) {
    ....
    case 2:
        from = [NSDate dateWithTimeIntervalSince1970:1388552400];
        [self refreshContents:from toDate:[NSDate date]];
        break;

}

Answer 6

Hard to be sure without looking at the code, but it probably means there's some variable declaration going on inside the switch and the compiler can't tell if there's a clear path to the required dealloc point.