How do I interpret precision and scale of a number

Question

I have the following column specified in a database: decimal(5,2)

How does one interpret this?

According to the properties on the column as viewed in SQL Server Management studio I can see that it means: decimal(Numeric precision, Numeric scale).

What do precision and scale mean in real terms?

It would be easy to interpret this as a decimal with 5 digits and two decimals places...ie 12345.12

P.S. I've been able to determine the correct answer from a colleague but had great difficulty finding an answer online. As such, I'd like to have the question and answer documented here on stackoverflow for future reference.

Answer 1

Precision, Scale, and Length in the SQL Server 2000 documentation reads:

Precision is the number of digits in a number. Scale is the number of digits to the right of the decimal point in a number. For example, the number 123.45 has a precision of 5 and a scale of 2.

Answer 2

Numeric precision refers to the maximum number of digits that are present in the number.

ie 1234567.89 has a precision of 9

Numeric scale refers to the maximum number of decimal places

ie 123456.789 has a scale of 3

Thus the maximum allowed value for decimal(5,2) is 999.99

Answer 3

Precision of a number is the number of digits.

Scale of a number is the number of digits after the decimal point.

What is generally implied when setting precision and scale on field definition is that they represent maximum values.

Example, a decimal field defined with precision=5 and scale=2 would allow the following values:

• 123.45 (p=5,s=2)
• 12.34 (p=4,s=2)
• 12345 (p=5,s=0)
• 123.4 (p=4,s=1)
• 0 (p=0,s=0)

The following values are not allowed or would cause a data loss:

• 12.345 (p=5,s=3) => could be truncated into 12.35 (p=4,s=2)
• 1234.56 (p=6,s=2) => could be truncated into 1234.6 (p=5,s=1)
• 123.456 (p=6,s=3) => could be truncated into 123.46 (p=5,s=2)
• 123450 (p=6,s=0) => out of range

Note that the range is generally defined by the precision: |value| < 10^p ...