On the server I have bare repository which is origin for development process and to simplify deployment to QA environment.
So in post-receive
it simply does
GIT_WORK_TREE=/home/dev git checkout -f
But as product gets more complicated there are some other things should be happening. So now it is handled by deploy.sh
script which is also tracked by repository. So what I want to do is to be able instead of checking out whole repository is to checkout only deploy.sh
and run it. I thought something like that would work:
SOURCE_PATH="/home/dev"
GIT_WORK_TREE=$SOURCE_PATH git checkout deploy.sh
$SOURCE_PATH"/deploy.sh"
But it does not work giving error:
error: pathspec 'deploy.sh' did not match any file(s) known to git.
What am I doing wrong? Or is it just impossible to do this way?
I know this is ooooooooold, but I found my own use-case for this functionality and looked around for a while for a better solution to this before combining a few solutions into a simple one-liner:
In my case, I just wanted to be able to "peek" into some of my bare repositories without unpacking the whole thing (some of them are huge). People were talking about sparse checkouts and other such things, but I just needed one-off functionality. To check out just the "Documents/Health Records" folder, for example, I would do the following:
And lo! There it did appear.
This git show or similar git cat-file blob approaches work more-or-less fine for text files, but they are hopeless for binary files.
Better approach which works reliably for any kind of files and even allows to checkout entire folders:
It creates a tar archive with desired content, exactly the file that sits in the source control. Works perfectly fine with binary files.
The only thing you need to do is to extract this tar file
See my blogpost for more details
As I explain in "checkout only one file from git", you cannot checkout just one file without cloning or fetching first.
But you
git show
that file, which means you can dump its content into a/another/path./deploy.sh
file, and execute that file.Since you execute that from a post-receive hook, the
git-show
will show the latest version of thedeploy.sh
file.The other alternative would be try
And checkout only that file, directly in your working tree.
The '
--
' help the git command to understand it is a file, not another parameter like a tag or a named branch.From the OP AlexKey's test, it requires that the working tree has been checked out (fully) at least once.