How to compare BSTR against a string in c/c++?

2019-04-20 14:10发布

wprintf(L"Selecting Audio Input Device: %s\n", 
                            varName.bstrVal);

if(0 == strcmp(varName.bstrVal, "IP Camera [JPEG/MJPEG]"))...

The above reports :

error C2664: 'strcmp' : cannot convert parameter 1 from 'BSTR' to 'const char *'

4条回答
贪生不怕死
2楼-- · 2019-04-20 14:39

I always construct _bstr_t wrappers around BSTRs. It makes things quite a bit easier and more idiomatic:

if(std::string("IP Camera [JPEG/MJPEG]") ==
                   static_cast<const char*>( _bstr_t(varName.bstrVal) )
{
}
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做个烂人
3楼-- · 2019-04-20 14:39

My solution:

static const std::wstring IPCamera = L"IP Camera [JPEG/MJPEG]";
if (varName.bstrVal == IPCamera {
  //...
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forever°为你锁心
4楼-- · 2019-04-20 14:43

As a richer alternative to the C runtime, you could use the Unicode CompareString or CompareStringEx APIs in Win32. If you don't have charset issues to consider, wcscmp is fine though.

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淡お忘
5楼-- · 2019-04-20 14:44

You have to use wcscmp instead:

if(0 == wcscmp(varName.bstrVal, L"IP Camera [JPEG/MJPEG]"))
{
}

Here is a description of the BSTR data type, it has a length prefix and a real string part which is just an array of WCHAR characters. It also has 2 NULL terminators.

The only thing to look out for is that the BSTR data type can contain embedded NULLs in the string portion, so wcscmp will only work in the cases where the BSTR does not contain embedded NULLs (which is probably most cases).

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