RenderPartial from different folder in RAZOR

2019-04-20 08:46发布

I've been trying to convert my aspx pages to cshtml and having an issue with rendering partial pages from another folder.

What I used to do:

<% Html.RenderPartial("~/Views/Inquiry/InquiryList.ascx", Model.InquiryList.OrderBy("InquiryId", MvcContrib.Sorting.SortDirection.Descending));%>

I would think that the equivalent would be:

@Html.RenderPartial("~/Views/Inquiry/_InquiryList.cshtml", Model.InquiryList.OrderBy("InquiryId", MvcContrib.Sorting.SortDirection.Descending))

This is obviously not working, I am getting the following error.

CS1973: 'System.Web.Mvc.HtmlHelper' has no applicable method named 'Partial' but appears to have an extension method by that name. Extension methods cannot be dynamically dispatched. Consider casting the dynamic arguments or calling the extension method without the extension method syntax.

How would I achieve this with using the Razor view engine?

3条回答
迷人小祖宗
2楼-- · 2019-04-20 09:07

The compiler cannot choose the correct method because your Model is dynamic. Change the call to:

@Html.RenderPartial("~/Views/Inquiry/_InquiryList.cshtml", (List<string>)Model.InquiryList)

Or to whatever data type InquiryList is.

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甜甜的少女心
3楼-- · 2019-04-20 09:26

The RenderPartial does not return a string or IHtmlString value. But does the rendering by calling Write in the Response.

You could use the Partial extension, this returns an MvcHtmlString

 @Html.Partial( ....

or

 @{ Html.RenderPartial(....);  }

If you really want RenderPartial

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ら.Afraid
4楼-- · 2019-04-20 09:29

Remember to include your strongly typed @model directive in your new Razor view. It is an easy step to miss when converting views from .aspx to .cshtml. If you forget, that 'System.Web.Mvc.HtmlHelper' has no applicable method named 'Partial' error message could appear.

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