How to use pagination in laravel 5?

Question

am trying to port my laravel4 application to laravel 5 . In the previous version i could use the following method for generating pagination urls .

In controller:

$this->data['pages']= Page::whereIn('area_id', $suburbs)->where('score','>','0')->orderBy('score','desc')->paginate(12);

and after sharing the data array with the view, i could user

In views :

{{$pages->links()}}

In laravel 5 the doing that results in following error

ErrorException in AbstractPaginator.php line 445:
call_user_func_array() expects parameter 1 to be a valid callback, class 'Illuminate\Support\Collection' does not have a method 'links'

not sure what i am missing here, can somebody help ?

Answer 1

@if ($posts->lastPage() > 1)
        <nav aria-label="Page navigation">
            <ul class="pagination">
                @if($posts->currentPage() != 1 && $posts->lastPage() >= 5)
                <li>
                    <a href="{{ $posts->url($posts->url(1)) }}" aria-label="Previous">
                        <span aria-hidden="true">First</span>
                    </a>
                </li>
                @endif
                @if($posts->currentPage() != 1)
                <li>
                    <a href="{{ $posts->url($posts->currentPage()-1) }}" aria-label="Previous">
                        <span aria-hidden="true">&#x3C;</span>
                    </a>
                </li>
                @endif
                @for($i = max($posts->currentPage()-2, 1); $i <= min(max($posts->currentPage()-2, 1)+4,$posts->lastPage()); $i++)
                @if($posts->currentPage() == $i)
                <li class="active">
                @else
                <li>
                @endif
                    <a href="{{ $posts->url($i) }}">{{ $i }}</a>
                </li>
                @endfor
                @if ($posts->currentPage() != $posts->lastPage())
                <li>
                    <a href="{{ $posts->url($posts->currentPage()+1) }}" aria-label="Next">
                        <span aria-hidden="true">&#x3E;</span>
                    </a>
                </li>
                @endif
                @if ($posts->currentPage() != $posts->lastPage() && $posts->lastPage() >= 5)
                <li>
                    <a href="{{ $posts->url($posts->lastPage()) }}" aria-label="Next">
                        <span aria-hidden="true">Last</span>
                    </a>
                </li>
                @endif
            </ul>
        </nav>
        @endif

Answer 2

Pagination Laravel 5.6.26, for the pagination the controller are :

Controller code (https://laravel.com/docs/5.6/pagination#basic-usage)

    posts = Post::orderBy('created_at','desc')->paginate(10);
    return view('posts.index')->with('posts', $posts);

Front end into blade (view) (https://laravel.com/docs/5.6/pagination#displaying-pagination-results)

   {{ $users->links() }}

Answer 3

In other frameworks, pagination can be very painful. Laravel 5 makes it a breeze. For using it, first you have to make a change in your controller code where you calling data from the database:

 public function index()
{       
        $users = DB::table('books')->simplePaginate(5);
        //using pagination method
        return view('index', ['users' => $users]);
}

...after that you can use this code:

<?php echo $users->render(); ?>

That will make you use simple Laravel 5 beauty.

Answer 4

Hi there is my code for pagination: Use in view:
@include('pagination.default', ['paginator' => $users])

Views/pagination/default.blade.php

@if ($paginator->lastPage() > 1)
    <ul class="pagination">
        <!-- si la pagina actual es distinto a 1 y hay mas de 5 hojas muestro el boton de 1era hoja -->
        <!-- if actual page is not equals 1, and there is more than 5 pages then I show first page button -->
        @if ($paginator->currentPage() != 1 && $paginator->lastPage() >= 5)
            <li>
                <a href="{{ $paginator->url($paginator->url(1)) }}" >
                    <<
                </a>
            </li>
        @endif

        <!-- si la pagina actual es distinto a 1 muestra el boton de atras -->
        @if($paginator->currentPage() != 1)
            <li>
                <a href="{{ $paginator->url($paginator->currentPage()-1) }}" >
                    <
                </a>
            </li>
        @endif

        <!-- dibuja las hojas... Tomando un rango de 5 hojas, siempre que puede muestra 2 hojas hacia atras y 2 hacia adelante -->
        <!-- I draw the pages... I show 2 pages back and 2 pages forward -->
        @for($i = max($paginator->currentPage()-2, 1); $i <= min(max($paginator->currentPage()-2, 1)+4,$paginator->lastPage()); $i++)
                <li class="{{ ($paginator->currentPage() == $i) ? ' active' : '' }}">
                    <a href="{{ $paginator->url($i) }}">{{ $i }}</a>
                </li>
        @endfor

        <!-- si la pagina actual es distinto a la ultima muestra el boton de adelante -->
        <!-- if actual page is not equal last page then I show the forward button-->
        @if ($paginator->currentPage() != $paginator->lastPage())
            <li>
                <a href="{{ $paginator->url($paginator->currentPage()+1) }}" >
                    >
                </a>
            </li>
        @endif

        <!-- si la pagina actual es distinto a la ultima y hay mas de 5 hojas muestra el boton de ultima hoja -->
        <!-- if actual page is not equal last page, and there is more than 5 pages then I show last page button -->
        @if ($paginator->currentPage() != $paginator->lastPage() && $paginator->lastPage() >= 5)
            <li>
                <a href="{{ $paginator->url($paginator->lastPage()) }}" >
                    >>
                </a>
            </li>
        @endif
    </ul>
@endif

Answer 5

In Laravel 5 there is no method "links" you can try this

{!! $pages->render() !!}