I have this scenario where I thought it would be pretty basic, but found out that I can't really achieve what I need. This is why I have this question for a thinking_sphinx's expert.
The scenario is this: I need do a search within a list of companies and only return those who has an address (there can be many address by company) which belongs to a particular city or none at all (this I can do).
I have the following models :
class Company < ActiveRecord::Base
has_many :company_addresses
define_index
indexes :name
indexes :description
indexes :keywords
end
end
and
class CompanyAddress < ActiveRecord::Base
end
The CompanyAddress has a city_id property. Without looping through all returned records from a sphinx search, is there a way to achieve the same thing more easily?
I'm using Rails 3.0.3 and thinking_sphinx.
You'll want to add an attribute pointing to the city_id values for the company:
And then you can filter on Companies belonging to a specific city:
If you want both matching to a specific city or has no cities, that's a little trickier, as OR logic for attribute filters is more than a little tricky at best. Ideally what you want is a single attribute that contains either 0, or all city ids. Doing this depends on your database, as MySQL and Postgres functions vary.
As a rough idea, though - this might work in MySQL:
Postgres is reasonably similar, though you may need to use a
CASE
statement instead ofIF
, and you'll definitely want to use a couple of functions for the group concatenation:(array_accum is provided by Thinking Sphinx, as there was no direct equivalent of GROUP_CONCAT in PostgreSQL).
Anyway, if you need this approach, and get the SQL all figured out, then your query looks something like:
This will match on either 0 (representing no cities), or the specific city.
Finally: if you don't reference the company_addresses association anywhere in your normal fields and attributes, you'll need to force to join in your
define_index
:Hopefully that provides enough clues - feel free to continue the discussion here or on the Google Group.