Taking subarrays from numpy array with given strid

Question

Lets say I have a Python Numpy array array a.

numpy.array([1,2,3,4,5,6,7,8,9,10,11].)

I want to create a matrix of sub sequences from this array of length 5 with stride 3. The results matrix hence will look as follows:

numpy.array([[1,2,3,4,5],[4,5,6,7,8],[7,8,9,10,11]])

One possible way of implementing this would be using a for-loop.

result_matrix = np.zeros((3, 5))
for i in range(0, len(a), 3):
  result_matrix[i] = a[i:i+5]

Is there a cleaner way to implement this is Numpy?

Answer 1

Approach #1 : Using broadcasting -

def broadcasting_app(a, L, S ):  # Window len = L, Stride len/stepsize = S
    nrows = ((a.size-L)//S)+1
    return a[S*np.arange(nrows)[:,None] + np.arange(L)]

Approach #2 : Using more efficient NumPy strides -

def strided_app(a, L, S ):  # Window len = L, Stride len/stepsize = S
    nrows = ((a.size-L)//S)+1
    n = a.strides[0]
    return np.lib.stride_tricks.as_strided(a, shape=(nrows,L), strides=(S*n,n))

Sample run -

In [143]: a
Out[143]: array([ 1,  2,  3,  4,  5,  6,  7,  8,  9, 10, 11])

In [144]: broadcasting_app(a, L = 5, S = 3)
Out[144]: 
array([[ 1,  2,  3,  4,  5],
       [ 4,  5,  6,  7,  8],
       [ 7,  8,  9, 10, 11]])

In [145]: strided_app(a, L = 5, S = 3)
Out[145]: 
array([[ 1,  2,  3,  4,  5],
       [ 4,  5,  6,  7,  8],
       [ 7,  8,  9, 10, 11]])