Limit a double to two decimal places [duplicate]

2019-01-06 20:36发布

How do I achieve the following conversion from double to a string:

1.4324 => "1.43"
9.4000 => "9.4"
43.000 => "43"

i.e. I want to round to to decimal places but dont want any trailing zeros, ie i dont want

9.4 => "9.40" (wrong)
43.000 => "43.00" (wrong)

So this code which I have now doesn't work as it displays excess zeros:

[NSString stringWithFormat: @"%.2f", total]

5条回答
虎瘦雄心在
3楼-- · 2019-01-06 21:09

The easiest way is to probably roll your own. I've had to do this in C before since there's no way to get the behavior you want with printf formatting.

It doesn't appear to be much easier in Objective-C either. I'd give this a try:

NSString *ftotal = [NSString stringWithFormat: @"%.2f", total];
while ([ftotal hasSuffix:@"0"]) {
    ftotal = [ftotal subStringToIndex [ftotal length]-1];
}
if ([ftotal hasSuffix:@"."]) {
    ftotal = [ftotal subStringToIndex [ftotal length]-1];
}

or this (possibly faster) variant:

NSString *ftotal = [NSString stringWithFormat: @"%.2f", total];
if ([ftotal hasSuffix:@".00"]) {
    ftotal = [ftotal subStringToIndex [ftotal length]-3];
} else {
    if ([ftotal hasSuffix:@"0"]) {
        ftotal = [ftotal subStringToIndex [ftotal length]-1];
    }
}

The stringWithFormat guarantees there will always be a ".nn" at the end (where n is a digit character). The while and if simply strip off trailing zeros and the trailing decimal if it was an integer.

Obviously, you may want to put it in a function or class so you can get at it from anywhere without having to duplicate the code all over the place.

查看更多
Deceive 欺骗
4楼-- · 2019-01-06 21:17

I am pretty sure that [[NSNumber numberWithFloat:f] stringValue] does exactly what you want.

查看更多
Deceive 欺骗
5楼-- · 2019-01-06 21:23

You made simple mistake. This will work:

[NSString stringWithFormat: @"%.2lf", total]
查看更多
我欲成王,谁敢阻挡
6楼-- · 2019-01-06 21:30

I'm not familiar with objective C, but this isn't possible with standard printf-style formatting.

Using %g would sort-of work, but for large or small numbers it would use scientific notation (eg 9.6e+6, 4.2e-7) rather than decimal notation.

The equivalent question was asked for C/C++ here, and in that case the answer is to use %f and then strip any trailing 0's from the string. Not exactly elegant.

查看更多
登录 后发表回答