Random array generation with no duplicates

2019-01-06 20:04发布

I am trying to create something that generates a random array with no duplicate values. I've already looked at other answers but none seem to help me understand. I cannot think of a way to actually generate random numbers that contain no duplicates. Here is what i have tried so far:

srand(time(NULL));
int numbers [4];

for (int x=0; x!=4;x++)
{
    numbers[x] = 1 + (rand() % 4) ;
    printf("%d ", numbers[x]);
}

Any help will be appreciated.

标签: c++ c random
9条回答
我欲成王,谁敢阻挡
2楼-- · 2019-01-06 20:57

First of all rand() is generatig random numbers but not wihout duplicates.

If you want to generate a random array without duplicates the rand() method is not working at all.

Let say you want to generate an array of 1000 numbers. In the best case let say you generated the first 999 numbers without duplicates and last think to do is generating the last number. The probability of getting that number is 1/1000 so this is almost going to take forever to get generated. In practice only 10 numbers makes a big trouble.

The best method is to generate all your numbers by incrementation (or strictly monotonic sequence) is shuffle them. In this case there will be no duplicates

Here is an exemple on how to do it with 10 numbers. Even with 1000 numbers it's working.

Note: Suffle function from Jhon Leehey's answer.

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

void shuffle(int *arr, size_t n)
{
    if (n > 1) 
    {
        size_t i;
        srand(time(NULL));
        for (i = 0; i < n - 1; i++) 
        {
          size_t j = i + rand() / (RAND_MAX / (n - i) + 1);
          int t = arr[j];
          arr[j] = arr[i];
          arr[i] = t;
        }
    }
}

int main()
{
    int i;
    int arr[10];
    for (i=0; i<10; i++){
        arr[i] = i;
    }
    shuffle(arr, 10);
    for (i=0; i<10; i++){
        printf("%d ", arr[i]);
    }
}
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Bombasti
3楼-- · 2019-01-06 20:57

There are 2 solutions to choose from:

  1. Generate random numbers using something like rand() and check for duplicates.

  2. Find a mathematical sequence that is strictly monotonic (preferably strictly increasing) and get its terms as members of your array. Then, you can shuffle your array. The result will not be truly random, but neither using rand() won't. rand() uses a simillar tehnique, and that is why we need to set the seed with something changeing, like time. You can use time for example to generate the first element of the sequence, and with a good sequence your results will be at least decent. Note that the sequence MUST be strictly monotonic, to avoid generation of duplicates. The sequence need not be too complex. For example, if you get unix time modulo 10000 as the first term and then you generate other terms using a reccurence like x[i] = x[i-1] + 3*x[i-2] should be fine. Of course, you may use more sophisticated sequences too, but be careful at overflow (as you can't apply modulo operator to the result, because it would not be increasing anymore) and the number of digits you would like to have.

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成全新的幸福
4楼-- · 2019-01-06 21:06

If you want to pseudo-randomly traverse a large space without maintaining visited indices, you should look at this project I contributed to years ago for the basic technique. http://packetfactory.openwall.net/projects/ipspace/index.html

You should be able to adapt it to your purposes, source is at the bottom of the page.

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