Java overloading and overriding

Question

We always say that method overloading is static polymorphism and overriding is runtime polymorphism. What exactly do we mean by static here? Is the call to a method resolved on compiling the code? So whats the difference between normal method call and calling a final method? Which one is linked at compile time?

Answer 1

i agree with rachel, because in K&B book it is directly mentioned that overloading does not belong to polymorphism in chapter 2(object orientation). But in lots of places i found that overloading means static polymorphism because it is compile time and overriding means dynamic polymorphism because it s run time.

But one interesting thing is in a C++ book (Object-Oriented Programming in C++ - Robert Lafore) it is also directly mentioned that overloading means static polymorphism. But one more thing is there java and c++ both are two different programing languages and they have different object manipulation techniques so may be polymorphism differs in c++ and java ?

Answer 2

Your are right - calls to overloaded methods are realized at compile time. That's why it is static.

Calls to overridden methods are realized at run-time, based on the type on which the method is invoked.

On virtual methods wikipedia says:

In Java, all non-static methods are by default "virtual functions." Only methods marked with the keyword final are non-virtual.

final methods cannot be overridden, so they are realized statically.

Imagine the method:

public String analyze(Interface i) {
     i.analyze();
     return i.getAnalysisDetails();
}

The compiler can't overload this method for all implementations of Interface that can possibly be passed to it.