how to throw a 403 error in Apache CXF - Java

2019-04-11 16:12发布

I am using the following code based on having an interceptor. When check returns true I want to throw a 403 error:

    @Override
    public void handleMessage(Message arg0) throws Fault {


        HttpServletRequest request = context.getHttpServletRequest();
        if(check(request)){
        // currently not working
                throw "Fault";
        }

I want to throw a 403 error. How do I go about doing that from this situation?

I am a little confused about how "throws fault" works.

Any help is appreciated

2条回答
劫难
2楼-- · 2019-04-11 17:11

Have you considered throwing:

throw new javax.ws.rs.ForbiddenException();

It returns http 403.

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聊天终结者
3楼-- · 2019-04-11 17:12

CXF will default the status code to 500 for a Fault, but you can set it with Fault.setStatusCode. For example

Fault fault = new Fault(new Exception("Exception message"));
fault.setStatusCode(403);
throw fault;
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