this is a really basic question (I hope). Most of the exception handling I have done has been with c#. In c# any code that errors out in a try catch block is dealt with by the catch code. For example
try
{
int divByZero=45/0;
}
catch(Exception ex)
{
errorCode.text=ex.message();
}
The error would be displayed in errorCode.text. If I were to try and run the same code in php however:
try{
$divByZero=45/0;
}
catch(Exception ex)
{
echo ex->getMessage();
}
The catch code is not run. Based on my limeted understanding, php needs a throw. Doesn't that defeat the entire purpose of error checking? Doesn't this reduce a try catch to an if then statement? if(dividing by zero)throw error Please tell me that I don't have to anticipate every possible error in a try catch with a throw. If I do, is there anyway to make php's error handling behave more like c#?
From http://php.net/manual/en/language.exceptions.php
"Internal PHP functions mainly use Error reporting, only modern Object oriented extensions use exceptions. However, errors can be simply translated to exceptions with ErrorException."
See also http://www.php.net/manual/en/class.errorexception.php
I think the only way to deal with this in PHP is to write:
Unlike in C#, not every issue will raise an exception in PHP. Some issues are silently ignored (or not silently - they print something to the output), but there are other ways to handle these. I suppose this is because exceptions were not a part of the language since the first version, so there are some "legacy" mechanisms.
You could also convert all your php errors with set_error_handler() and ErrorException into exceptions:
PHP's try-catch was implemented later in the language's life, and so it only applies to user-defined exceptions.
If you really want to handle actual errors, set your own error handler.
To define and catch exceptions: