How to pass parameters from command line to $_POST

Question

I know this could sound a little weird but I need to pass some parameters to a $_POST array. Similar to the way apache does it, or any other web server.

Unfortunately I couldn't find libapache2-mod-php5 anywhere for my Ubuntu.

Answer 1

That's not easily doable. You can invoke the php-cgi binary and pipe a fake POST request in. But you'll need to set up a whole lot of CGI environment variables:

echo 'var1=123&var2=abc' | REQUEST_METHOD=POST  SCRIPT_FILENAME=script.php REDIRECT_STATUS=CGI CONTENT_TYPE=application/www-form-urlencoded php-cgi 

Note: Insufficient, doesn't work like that. But something like that...

---

It's certainly easier if you just patch the script, and let it load the $_POST array from a predefined environment variable.

$_POST = parse_url($_SERVER["_POST"]);

Then you can invoke it like _POST=var=123 php script.php for simplicity.

Answer 2

I was searching for a solution for this and came by, because it was the first hit at Google. The second one was somehow mor useful for me, because it has a really easy solution, if you have access to the PHP script and can change it.

Just insert the following lines at the beginning of your script:

/* if started from commandline, wrap parameters to $_POST and $_GET */
if (!isset($_SERVER["HTTP_HOST"])) {
  parse_str($argv[1], $_GET);
  parse_str($argv[1], $_POST);
}

This small piece of code does the trick (you may decide if you want to use $_GET or $_POST or, like I needed it, both.
After changing your script you can call it from commandline passing your args:

php yourscript.php 'arg1=x&arg2=y'

Have fun!

Answer 3

use curl to post data
curl --data "name=ii" "param1=value1&param2=value2" http://test.com/sample.php