C# Right click on TreeView nodes

Question

I have a TreeView with the parent node : Node0. I add 3 subnodes:

Node01
Node02
Node03

I have a popup menu that is associate to each of the subnodes.

My problem: If I right-click directly to one of the subnodes, my popup does not display. So I have to Select the Subnode first and Right-click to have the popup displayed.

1. How can I change the code so that the Direct Right-Click on a specific SubNode open the PopupMenu?
2. The popupMenu have only OpenMe menu in the list. When clicking on this menu, a windows is supposed to open and this windows should be associated to the submenu I have clicked. How to get the Event of the right-click submenu and display Form with it?

EDIT:

Look at this

private void modifySettingsToolStripMenuItem_Click(object sender, EventArgs e)
    {
        try
        {
            String s = treeView1.SelectedNode.Text;
            new chartModify(s).ShowDialog();
        }
        catch (Exception er)
        {
            System.Console.WriteLine(">>>" + er.Message);
        }
    }

The line String s = treeView1.SelectedNode.Text; gets the name of the selected node and not the node that have been right-clicked.

So here I have to modify this piece of code with the

private void treeview1_NodeMouseClick(object sender, TreeNodeMouseClickEventArgs e)
        {
            if (e.Button == MouseButtons.Right)
                MessageBox.Show(e.Node.Name);
        }

I modify it like this:

try
        {
            TreeNodeMouseClickEventArgs ee;
            new chartModify(ee.Node.Name).ShowDialog();
        }

but it does not work : Error:Use of unassigned local variable 'ee'

EDIT #2: Finaly got the solution

public string s;
private void modifySettingsToolStripMenuItem_Click(object sender, EventArgs e)
        {
            try
            {
                new chartModify(s).ShowDialog();
            }
            catch (Exception er)
            {
                System.Console.WriteLine(">>>" + er.Message);
            }
        }

and then

private void treeview1_NodeMouseClick(object sender, TreeNodeMouseClickEventArgs e)
        {
            if (e.Button == MouseButtons.Right)
            {
                s = e.Node.Name;
                menuStrip1.Show();
            }
        }

it works,
Thanks

Answer 1

You can try using the NodeMouseClick Event it uses the TreeNodeClickEventArgs to get the Button and the Node that was clicked.

private void treeView1_NodeMouseClick(object sender, TreeNodeMouseClickEventArgs e)
{
    if(e.Button == MouseButtons.Right)
        MessageBox.Show(e.Node.Name);
}

---

Modified Code to show Popup and created Form

public partial class Form1 : Form
{
    string clickedNode;
    MenuItem myMenuItem = new MenuItem("Show Me");
    ContextMenu mnu = new ContextMenu();
    public Form1()
    {
        InitializeComponent();
        mnu.MenuItems.Add(myMenuItem);
        myMenuItem.Click += new EventHandler(myMenuItem_Click);
    }

    void myMenuItem_Click(object sender, EventArgs e)
    {
        Form frm = new Form();
        frm.Text = clickedNode;
        frm.ShowDialog(this);
        clickedNode = "";
    }

    private void treeView1_NodeMouseClick(object sender, TreeNodeMouseClickEventArgs e)
    {
        if (e.Button == MouseButtons.Right)
        {
            clickedNode = e.Node.Name;
            mnu.Show(treeView1,e.Location);
        }
    }
}

Answer 2

This will give you the treenode at a particular mouse point when your right click.

if(e.Button == MouseButtons.Right)
        {
            TreeNode destinationNode = ((TreeView)sender).GetNodeAt(new Point(e.X, e.Y));
            //Do stuff
        }

From here you should be able to open a specific popup menu.