Symfony parse error in output.php when creating pr

2019-04-09 14:06发布

Installed laravel 5.6 Have PHP 7.0 installed as well. When I try

laravel new sample-project 

it creates the required files and dependencies but bails with an error below:

PHP Parse error:  syntax error, unexpected '?', expecting variable (T_VARIABLE) in /home/johndoe/laravel/sample-project/vendor/symfony/console/Output/Output.php on line 40

Have a feeling this might be due to issues with the symfony file but not sure how to go about getting the right version or making a change in Output.php

Trying any other command such as

php artisan list

results in the same error

Composer relevant section denoting laravel 5.6 / php 7.1.3

"require": {
    "php": "^7.1.3",
    "fideloper/proxy": "~4.0",
    "laravel/framework": "5.6.*",
    "laravel/tinker": "~1.0"
},

Any help would be appreciated.

EDIT

Based on the answer I had to create a project with laravel version 5.5 which means I had to use

composer create-project laravel/laravel sample-project "5.5.*"

That worked.

2条回答
Evening l夕情丶
2楼-- · 2019-04-09 14:25

I ended up having to edit the $PATH in my .bashrc file, because it was picking up an old version of php.

> whereis php
> echo $PATH

I found the correct version of php here: /opt/php71/bin

So now my .bashrc file looks like this:

export PATH=/opt/php71/bin:$PATH

This fixed the error I was getting in composer, AND now php artisan also works!

:-D

PS. The version of php that you're using in the shell may be different from the version used to serve your site. That can be fixed in cpanel's php selector.

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狗以群分
3楼-- · 2019-04-09 14:35

Laravel 5.6 requires PHP > 7.1.3

you will need to make sure your server meets the following requirements:

PHP >= 7.1.3
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