Serialize an object to XML

2018-12-31 09:25发布

I have a C# class that I have inherited. I have successfully "built" the object. But I need to serialize the object to XML. Is there an easy way to do it?

It looks like the class has been set up for serialization, but I'm not sure how to get the XML representation. My class definition looks like this:

[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://www.domain.com/test")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "http://www.domain.com/test", IsNullable = false)]
public partial class MyObject
{
  ...
}

Here is what I thought I could do, but it doesn't work:

MyObject o = new MyObject();
// Set o properties
string xml = o.ToString();

How do I get the XML representation of this object?

14条回答
看风景的人
2楼-- · 2018-12-31 10:28
    string FilePath = ConfigurationReader.FileLocation;   //Getting path value from web.config            
    XmlSerializer serializer = new XmlSerializer(typeof(Devices)); //typeof(object)
            MemoryStream memStream = new MemoryStream();
            serializer.Serialize(memStream, lstDevices);//lstdevices : I take result as a list.
            FileStream file = new FileStream(folderName + "\\Data.xml", FileMode.Create, FileAccess.ReadWrite); //foldername:Specify the path to store the xml file
            memStream.WriteTo(file);
            file.Close();

You can create and store the result as xml file in the desired location.

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长期被迫恋爱
3楼-- · 2018-12-31 10:29

Here's a basic code that will help serializing the C# objects into xml:

using System;

public class clsPerson
{
  public  string FirstName;
  public  string MI;
  public  string LastName;
}

class class1
{ 
   static void Main(string[] args)
   {
      clsPerson p=new clsPerson();
      p.FirstName = "Jeff";
      p.MI = "A";
      p.LastName = "Price";
      System.Xml.Serialization.XmlSerializer x = new System.Xml.Serialization.XmlSerializer(p.GetType());
      x.Serialize(Console.Out, p);
      Console.WriteLine();
      Console.ReadLine();
   }
}    
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