File upload with Jersey : FormDataContentDispositi

2019-04-09 10:55发布

I'm trying to implement file upload with Jersey so I followed this example : http://www.mkyong.com/webservices/jax-rs/file-upload-example-in-jersey/ which worked well with an HTML page. Now I adapted it to my application, here is code :

  public Response uploadFile(
    @FormDataParam("file") InputStream uploadedInputStream,
    @FormDataParam("file") FormDataContentDisposition fileDetail)
    throws IOException {

Response.Status respStatus = Response.Status.OK;

if (fileDetail == null) {
    respStatus = Response.Status.INTERNAL_SERVER_ERROR;
} else {
    try {
    initPath();
    if (fileDetail.getSize() > OntoWebStudioUtil
        .getUploadFileLimit()) {
        respStatus = Response.Status.NOT_ACCEPTABLE;
        return Response.status(respStatus).build();
    }

    writeToFile(uploadedInputStream, tempDirectory);
    } catch (Exception e) {
    respStatus = Response.Status.INTERNAL_SERVER_ERROR;
    e.printStackTrace();
    }
}
return Response.status(respStatus).build();
}

But with debug view, once I uploaded my picture and pushed the button send and then get here, uploadedInputStream and fileDetail are null. So I can do nothing... I am a beginner with Servlet and then REST, so please be indulgent.

Thank you.

标签: java rest jersey
1条回答
Explosion°爆炸
2楼-- · 2019-04-09 11:21

I found why it wasn't working : It is because the name you choose after the FormDataParameter("myForm") has to be the same as the name you choosed in your HTML form (name = "myForm")

So,

@FormDataParam("myForm") InputStream uploadedInputStream,
@FormDataParam("myform") FormDataContentDisposition fileDetail)

And the form has to be like

    <form action=".../rest/fileupload" method="post" enctype="multipart/form-data">
   <p>
    Select a file : <input type="file" name="myForm"/>
   </p>
   <input type="submit" value="Upload It" />
</form>

Hope it will help some other beginners like me :)

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