How to initialize an array in Java?

2018-12-31 09:49发布

I am initializing an array data like this :

public class Array {

    int data[] = new int[10]; 
    /** Creates a new instance of Array */
    public Array() {
        data[10] = {10,20,30,40,50,60,71,80,90,91};
    }

}

NetBeans points an error at the line

data[10] = {10,20,30,40,50,60,71,80,90,91};

How can I solve the problem?

10条回答
路过你的时光
2楼-- · 2018-12-31 10:16

Syntax

 Datatype[] variable = new Datatype[] { value1,value2.... }

 Datatype variable[]  = new Datatype[] { value1,value2.... }

Example :

int [] points = new int[]{ 1,2,3,4 };
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只若初见
3楼-- · 2018-12-31 10:20

Maybe this will work:

public class Array {

    int data[] = new int[10]; 
    /* Creates a new instance of Array */
    public Array() {
        data= {10,20,30,40,50,60,71,80,90,91};
    }
}
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其实,你不懂
4楼-- · 2018-12-31 10:21
data[10] = {10,20,30,40,50,60,71,80,90,91};

The above is not correct (syntax error). It means you are assigning an array to data[10] which can hold just an element.

If you want to initialize an array, try using Array Initializer:

int[] data = {10,20,30,40,50,60,71,80,90,91};

// or

int[] data;
data = new int[] {10,20,30,40,50,60,71,80,90,91};

Notice the difference between the two declarations. When assigning a new array to a declared variable, new must be used.

Even if you correct the syntax, accessing data[10] is still incorrect (You can only access data[0] to data[9] because index of arrays in Java is 0-based). Accessing data[10] will throw an ArrayIndexOutOfBoundsException.

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浪荡孟婆
5楼-- · 2018-12-31 10:21

When you create an array of size 10 it allocated 10 slots but from 0 to 9. This for loop might help you see that a little better.

public class Array {
    int[] data = new int[10]; 
    /** Creates a new instance of an int Array */
    public Array() {
        for(int i = 0; i < data.length; i++) {
            data[i] = i*10;
        }
    }
}
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