Calculating shortest path between 2 points on a fl

Question

How do you draw the curve representing the shortest distance between 2 points on a flat map of the Earth?

Of course, the line would not be a straight line because the Earth is curved. (For example, the shortest distance between 2 airports is curved.)

EDIT: THanks for all the answers guys - sorry I was slow to choose solution :/

Answer 1

To draw the 3D shortest path between two points on Earth's surface onto a 2D map of Earth's surface, you have to know how the 3D surface of Earth was projected onto the 2D map in question. If you know the projection used, you just need to apply it to the 3D shortest path to project it onto the 2D map. If you don't know the exact projection used, but have access to it through some sort of interface (ie. input 3D surface coords -> output 2D map coords), you could sample points along the 3D surface path, generate their corresponding map points through said interface, and then approximate the projected path with line segments/bezier curves/etc. through the projected sample points.

Answer 2

I get this sort of information from the Aviation Formulary.

In this case:

Distance between points

The great circle distance d between two points with coordinates {lat1,lon1} and {lat2,lon2} is given by:

d=acos(sin(lat1)*sin(lat2)+cos(lat1)*cos(lat2)*cos(lon1-lon2))

A mathematically equivalent formula, which is less subject to rounding error for short distances is:

d=2*asin(sqrt((sin((lat1-lat2)/2))^2 + cos(lat1)*cos(lat2)*(sin((lon1-lon2)/2))^2))

And

Intermediate points on a great circle

In previous sections we have found intermediate points on a great circle given either the crossing latitude or longitude. Here we find points (lat,lon) a given fraction of the distance (d) between them. Suppose the starting point is (lat1,lon1) and the final point (lat2,lon2) and we want the point a fraction f along the great circle route. f=0 is point 1. f=1 is point 2. The two points cannot be antipodal ( i.e. lat1+lat2=0 and abs(lon1-lon2)=pi) because then the route is undefined. The intermediate latitude and longitude is then given by:

    A=sin((1-f)*d)/sin(d)
    B=sin(f*d)/sin(d)
    x = A*cos(lat1)*cos(lon1) +  B*cos(lat2)*cos(lon2)
    y = A*cos(lat1)*sin(lon1) +  B*cos(lat2)*sin(lon2)
    z = A*sin(lat1)           +  B*sin(lat2)
    lat=atan2(z,sqrt(x^2+y^2))
    lon=atan2(y,x)