Open Facebook page from Android app?

Question

from my Android app, I would like to open a link to a Facebook profile in the official Facebook app (if the app is installed, of course). For iPhone, there exists the fb:// URL scheme, but trying the same thing on my Android device throws an ActivityNotFoundException.

Is there a chance to open a Facebook profile in the official Facebook app from code?

Answer 1

I have created a method to open facebook page into facebook app, if app is not existing then opening in chrome

    String socailLink="https://www.facebook.com/kfc";
    Intent intent = new Intent(Intent.ACTION_VIEW);
    String facebookUrl = Utils.getFacebookUrl(getActivity(), socailLink);
    if (facebookUrl == null || facebookUrl.length() == 0) {
        Log.d("facebook Url", " is coming as " + facebookUrl);
        return;
    }
    intent.setData(Uri.parse(facebookUrl));
    startActivity(intent);

Utils.class add these method

public static String getFacebookUrl(FragmentActivity activity, String facebook_url) {
    if (activity == null || activity.isFinishing()) return null;

    PackageManager packageManager = activity.getPackageManager();
    try {
        int versionCode = packageManager.getPackageInfo("com.facebook.katana", 0).versionCode;
        if (versionCode >= 3002850) { //newer versions of fb app
            Log.d("facebook api", "new");
            return "fb://facewebmodal/f?href=" + facebook_url;
        } else { //older versions of fb app
            Log.d("facebook api", "old");
            return "fb://page/" + splitUrl(activity, facebook_url);
        }
    } catch (PackageManager.NameNotFoundException e) {
        Log.d("facebook api", "exception");
        return facebook_url; //normal web url
    }
}

and this

 /***
 * this method used to get the facebook profile name only , this method split domain into two part index 0 contains https://www.facebook.com and index 1 contains after / part
 * @param context contain context
 * @param url contains facebook url like https://www.facebook.com/kfc
 * @return if it successfully split then return "kfc"
 *
 * if exception in splitting then return "https://www.facebook.com/kfc"
 *
 */
 public static String splitUrl(Context context, String url) {
    if (context == null) return null;
    Log.d("Split string: ", url + " ");
    try {
        String splittedUrl[] = url.split(".com/");
        Log.d("Split string: ", splittedUrl[1] + " ");
        return splittedUrl.length == 2 ? splittedUrl[1] : url;
    } catch (Exception ex) {
        return url;
    }
}

Answer 2

this is the simplest code for doing this

public final void launchFacebook() {
        final String urlFb = "fb://page/"+yourpageid;
        Intent intent = new Intent(Intent.ACTION_VIEW);
        intent.setData(Uri.parse(urlFb));

        // If a Facebook app is installed, use it. Otherwise, launch
        // a browser
        final PackageManager packageManager = getPackageManager();
        List<ResolveInfo> list =
            packageManager.queryIntentActivities(intent,
            PackageManager.MATCH_DEFAULT_ONLY);
        if (list.size() == 0) {
            final String urlBrowser = "https://www.facebook.com/pages/"+pageid;
            intent.setData(Uri.parse(urlBrowser));
        }

        startActivity(intent);
    }

Answer 3

To launch facebook page from your app, let urlString = "fb://page/your_fb_page_id"

To launch facebook messenger let urlString = "fb-messenger://user/your_fb_page_id"

FB page id is usually numeric. To get it, goto Find My FB ID input your profile url, something like www.facebook.com/edgedevstudio then click "Find Numberic ID".

Voila, you now have your fb numeric id. replace "your_fb_page_id" with the generated Numeric ID

 val intent = Intent(Intent.ACTION_VIEW, Uri.parse(urlString))
 if (intent.resolveActivity(packageManager) != null) //check if app is available to handle the implicit intent
 startActivity(intent)

Answer 4

To do this we need the "Facebook page id", you can get it :

• from the page go to "About".
• go to "More Info" section.

To opening facebook app on specified profile page,

you can do this:

 String facebookId = "fb://page/<Facebook Page ID>";
  startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(facebookId)));

Or you can validate when the facebook app is not installed, then open the facebook web page.

String facebookId = "fb://page/<Facebook Page ID>";
String urlPage = "http://www.facebook.com/mypage";

     try {
          startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(facebookId )));
        } catch (Exception e) {
         Log.e(TAG, "Application not intalled.");
         //Open url web page.
         startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(url)));
        }

Answer 5

Answering this in October 2018. The working code is the one using the pageID. I just tested it and it is functional.

public static void openUrl(Context ctx, String url){
    Uri uri = Uri.parse(url);
    if (url.contains(("facebook"))){
        try {
            ApplicationInfo applicationInfo = ctx.getPackageManager().getApplicationInfo("com.facebook.katana", 0);
            if (applicationInfo.enabled) {
                uri = Uri.parse("fb://page/<page_id>");
                openURI(ctx, uri);
                return;
            }
        } catch (PackageManager.NameNotFoundException ignored) {
            openURI(ctx, uri);
            return;
        }
    }

Answer 6

Intent intent = null;
    try {
        getPackageManager().getPackageInfo("com.facebook.katana", 0);
        String url = "https://www.facebook.com/"+idFacebook;
        intent = new Intent(Intent.ACTION_VIEW, Uri.parse("fb://facewebmodal/f?href="+url));
    } catch (Exception e) {
        // no Facebook app, revert to browser
        String url = "https://facebook.com/"+idFacebook;
        intent = new Intent(Intent.ACTION_VIEW);
        intent .setData(Uri.parse(url));
    }
    this.startActivity(intent);