How to remove view on the child's parent? andr

2019-04-08 08:32发布

So i have a button that displays an alert dialog when its clicked. I create the view for the alert dialog in the onCreate method of my activity. The code for that is right here:

    LayoutInflater factory = LayoutInflater.from(this);
    view = factory.inflate(R.layout.grade_result, null);

When i push the button for the first time, the dialog displays the way i want it, but when i push it a second time it throws this exception

11-28 00:35:58.066: E/AndroidRuntime(30348): Caused by: java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.

My code for the method that displays the AlertDialog when the button is pushed is right here:

public void details(View v){
    final AlertDialog.Builder alert = new AlertDialog.Builder(this);
    alert.setView(view);
    alert.setMessage("Details About Your Grades")
    .setCancelable(false)
    .setPositiveButton("Continue", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int id){
            dialog.cancel();

        }
    });
    alert.show();

Any help would be appreciated! Thank you!

7条回答
你好瞎i
2楼-- · 2019-04-08 08:55

It says that your "view" was connected to parent. It's happend when you called .setView(view). If i'm right - alertDialog class gives parent for your view. It is basics for android. ViewGroup may have a lot of child View's. I had similar problem. So, you can try this insinde onClick:

ViewGroup vGroup = view.getParent();
vGroup.removeView(view);
// And right after that - close dialog
dialog.dismiss();

It helped me, I hope it'll help you!

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Rolldiameter
3楼-- · 2019-04-08 08:57

Use alert.create(); then alertd.dismiss(); to destroy dialog

 final AlertDialog.Builder alert = new AlertDialog.Builder(this);
        final AlertDialog alertd = alert.create();

        alert.setTitle("Title");
        alert.setMessage("Messaage");

        alert.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
          public void onClick(DialogInterface dialog, int whichButton) {
            // Canceled.
              dialog.cancel();
              alertd.dismiss();
          }
        });
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劳资没心,怎么记你
4楼-- · 2019-04-08 08:59

Inflating the view that should be set within the Builder of the AlertDialog worked for me :

Button mButton = (Button) findViewById(R.id.my_button);
mButton.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            // inflating view out of the onClick() method does not work
            LayoutInflater mInflater = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            final ViewGroup viewGroup= (ViewGroup) mInflater.inflate(R.layout.my_view, null);

            Dialog alertDialog = new AlertDialog.Builder(getActivity())
                    .setTitle(R.string.my_title)
                    .setView(viewGroup)
                    .setPositiveButton(R.string.ok, new DialogInterface.OnClickListener() {
                        @Override
                        public void onClick(DialogInterface dialog, int which) {
                            dialog.dismiss();
                        }
                    }).create();
            alertDialog.show();
        }
}
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\"骚年 ilove
5楼-- · 2019-04-08 09:00

I had similar issue with alert dialog. First time I inflated a view and second time I wanted to display a message. If you display the alert dialog once then you inflate the view and the dialog is cached. If you display it second time you get the error IllegalStateException:"call removeView() on child's parent first"

I solved this issue by removing the view that I inflated on first click and displayed the message on second click. -remove the view or message every time before you inflate or create a message.

alertDialogBuilder.setView(null).setMessage(null);
alertDialogBuilder.setView(yourView).setMessage(yourMessage);

I modified Your code and it work's fine with me.

LayoutInflater factory = LayoutInflater.from(this);
mView = factory.inflate(R.layout.grade_result, null);

public void details(View v){
    final AlertDialog.Builder alert = new AlertDialog.Builder(this);
    alert.setView(null).setMessage(null);
    alert.setView(mView);
    alert.setMessage("Details About Your Grades")
    .setCancelable(false)
    .setPositiveButton("Continue", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int id){
            dialog.cancel();

        }
    });
    alert.show(); }
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疯言疯语
6楼-- · 2019-04-08 09:02

you can set View to null before setting the view in the dialog.
just like this:

alert.setView(null);
alert.setView(view);

It will always set view to null before setting it again.

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ゆ 、 Hurt°
7楼-- · 2019-04-08 09:04

Use this :

final AlertDialog.Builder alert = new AlertDialog.Builder(ProductsListAfterFilter.this);
alert.setTitle("Добавить продукт в корзину?");
alert.setMessage("Введите количество: ");

// Set an EditText view to get user input
final EditText input = new EditText(ProductsListAfterFilter.this);
alert.setView(input);

alert.setPositiveButton("Ok", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
        int value = 0 ;
    try {
            value = Integer.valueOf(input.getText().toString());
    }
    catch (Exception err){
            Toast.makeText(getApplicationContext(), "Введите число", 100).show();
    }
    //insertValue(value,st1,st2,st3,st4);
    Toast.makeText(getApplicationContext(), "value = "+value, 100).show();
    dialog.dismiss();
    dialog.cancel();
    }
});

alert.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
    public void onClick(DialogInterface dialog, int whichButton) {
    // Canceled.
        dialog.cancel();
        dialog.dismiss();

    }
});


final AlertDialog alertd = alert.create();
alertd.show();
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